06 AET - Genset Sizing

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    Genset Sizing

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    Required Information

    Duty rating to be applied

    Frequency (50Hz/60Hz)

    Nominal Voltage

    Climatic Conditions

    Voltage and Frequency dip requirement

    Load parameters

    Mandatory load steps or sequence of load step, if they exist

    Number of genset in parallel

    Sizing software(Power-Suite)

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    Motor Load

     AC electric motors represent inductive loads withlagging power factors

    Different types of motors have different starting

    characteristics.

    Starting characteristics may drive the need for a

    larger or smaller generator.

    Starting an electric motor can create voltage dips in

    excess of 40% if the genset is not properly sized.

    Cummins Confidential

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    Inductive Load: kW vs. KVars

    Inductive loads need two kinds of power to function properly:

     –  Active power (kW) – actually performs the work

     –  Reactive power (kvar) – maintains the electromagnetic fields

    Engines Produce kW--Fuel Rate Controls

     Alternators Make kVAR--Excitation Controls

    kW Dem anded b y Load

    kVa r Dem anded b y Lo ad

    kW = engine

       k   V   A

       R   =

      a   l   t  e  r  n

      a   t  o  rppa r en t pow e r

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    Voltage Response at Constant Speed

    Voltage

    requency

    Generator Transient Response to StepLoads

     Alternator Must Support kVA:

     – Limit Initial Dip

     – Recover to Acceptable Voltage(Motor Torque Proportional to

    Voltage2

    Engine Must Support kW (Similarto Voltage Response)

    Dynamic Response Combination ofFrequency and Voltage

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    We are going to create a project with PowerSuite with thefollowing criterias:

    50Hz

    400V

    Min rated capacity 30%

    18% Voltage Dip, 5% Frequency Dip

    25C

    150m

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     Electrical Motors

      UPS

      Lighting

     Regenerative loads

     Miscellaneous load

    Differents types of loads

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     Apply Alternative Starting Methods on HighInertia Loads With Caution

    Motor Torque Proportional to

     Appl ied (Vol tage)2 Okay for low inertia applications.

    Watch out with high loads!

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    Typical 3 Ø Induction MotorCharacteristics

    Direct On-Line (DOL) Start

    High Locked Rotor Currentand KVA

    Torque Shown for 100%

    Rated Voltage (sol id red line) Starting (instantaneous) PF

    0.2 to 0.4 for 3 Ø Motors

    Higher StartingRequirements for HighEfficiency 3Ø and for 1Ø

    Treat Synchronous MotorsLike Induction Motors

       P   E

       R   C   E   N   T   T   O   R   Q   U   E ,   P   O   W

       E   R ,   C   U   R   R   E   N   T

    PERCENT MOTOR RATED SPEED 

    20 40 60 80 100 

    100  0.2 

    1.0 

       P   O   W   E   R   F   A   C   T   O   R   (   L

       A   G   G   I   N   G   ) 

    600 

    Current 

    Power Factor  

    Load Torque

    Motor Torque

    Power

    0

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    Let’s enter the following load with direct on line starting

    method in Powersuite:

    Motor Running Power (Electrical) = 300kWe, 350kVA

    Starting kVA = 6 x 350kVA = 2100kVA

    Starting kW = 2100kVA x 0.3 p.f. = 630kW

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    Star-delta Starting…

    Reduced Starting Impact

    Watch out for the transition(kVA)

    Potential start failure ifalternator cannot sustainvoltage in transit ion.

    Typical kVA demand of motor…

    Typical kW demand of motor…

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    Transit ion on Reduced Voltage Starters

    Same as DOLTrue Reduced

    Voltage

    Transition

    too Early

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    We will now enter the following load with star/delta startingmethod in PowerSuite:

    Motor Running Power (Electrical) = 300kWe, 350kVA

    Starting kVA = 3 x 350kVA = 1050kVA

    Starting kW = 1050kVA x 0.3 p.f. = 315kW

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     Auto TransformerThis method uses transformer action to reduce the voltage applied to the motor  

    and current seen by the supply. An improved torque/amp ratio is achieved and

    starting current is typically 3 x FLC, depending on the voltage tapping selected.Normally the voltage is applied to the motor  in voltage steps through the T/F

    taps being selected through contactors. Typical tappings are 50%, 70%,

    followed by full voltage being applied to the motor . The major disadvantages

    are size & cost. Mechanical snatch at switch on is not controllable and may

    cause problems. Once tappings have

    been selected, it may be necessary tochange them according to changes in

    load parameters.

     Advantages

    • Simple operation

    Disadvantages

    • Poor controllability

    • Bulky

    • Very Expensive

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    Soft Starters Limit the starting current by limiting the amount of

    starting torque. Current distortion has to be considered for the non

    linear loads.

     Advantages: Less mechanical stress, reduced startcurrent, improved control of acceleration and

    deceleration

    Disadvantages:

    Size & Cost

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    Uninterruptible Power Supply

    UPS can produce high levels of

    current distortion.

    Excessive generator voltage

    distortion

    Increased Power SystemComponent losses and heating

    Harmonics can be reduced by

    filters on the UPS.

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    (Or 18 Pulse)

    Cummins Confidential

    Phase Controlled Rectif iers: Voltage andCurrent Distortion

    3 1

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    Let’s enter the following UPS Load in PowerSuite

    Rated Output= 200kVA

    Rectifier= 12 Pulses

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    Lighting Loads

    Fluorescent & Discharge 

    Both are non-linear loads which may need to be

    considered when sizing your generator

    Incandescent 

    Defined as a general load for sizing purposes

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    Let’s enter the following light ing load in PowerSuite

    Light Type : Fluorescent

    Running KVA = 50kVA

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    Regenerative Load

    Reverse power needs to be considered.

    http://upload.wikimedia.org/wikipedia/commons/5/55/Gondola_car_20060409.jpg

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    Regenerative Load

    Stage 1:-

    Genset Supplies Site Loads

    Stage 2:-

    Lift Motor Produces

    Reverse Power 200kW

    100kW Load Bank Removes

    Risk of Reverse Power

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    Miscellaneous Loads

    If the load is so specific that you can not find its kind in PowerSuite,you can create your own kind of load

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    Let’s enter the following load in PowerSuite

    Running & Starting = 100 kW

    Running Power factor= 0.95

    Starting Power factor= 0.50

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    We are going to size the genset with a single load step and the load weentered:

    (In case a single genset is not enough to start the loads with the criteriasit is possible to add more gensets)

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    Size of genset optimization

    Step Starting Sequence

    Step Loading the Generator

    • Apply Load in Increments

    • Apply Large Motor Loads First

    • Limit Voltage and Frequency dip

    • Ultimately reduce genset size 

    Let’s now optimise the genset size

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    Questions?

    27

    Thank You