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7/25/2019 Bac2011_M1
1/5
1
--2011
))3
)-1
:
-
-
)
(
(
:3 2 5 3 2 5 2CH COOH C H OH CH COO C H H O + = +
(
E:
.
:=25t h)-2
30,6 9 10 /66,7
acdnv mol hdt
= = =
1a cn x=
( ) 319 10
d x
dt
=
3
9 10 /dx
mol hdt
=
25t h=.
:)
0,34a cn mol =
1 0,34qx =0,66qx mol=
1m mol=
0,66
100 100 66%1
q
m
xr
x= = =
3-
.
4-([ ] [ ]
[ ] [ ]
( )
( )
23 2 5 2
2
3 2 5
0,663,77
0,34
qq ester eq
ac al q q
CH COO C H H O n nQ
CH COOH C H OH n n
= = = =
= =3,77qK Q
(
0t=
.
.
( )
( )( )
20,66
2,370, 34 0, 54
riQ = =
>riQ K
) .(
3 2 5 2 5 2CH COOH C H OH HCOO C H H O + = +
0011
x11 x
qxq1 q1 qx
mxm1 mx1 m
3 2 5 2 5 2CH COOH C H OH HCOO C H H O + = +
0,660,660,540 , 3 4
0,66 +0,66 +0,54 0,34
50 100( )t h
( )aciden mol
0,2
25
7/25/2019 Bac2011_M1
2/5
2
))3
:-1
P ma=r
r
mg ma=r r
=a gr r
Oxuur
:0a=Ozuur
:a g=
:)
:)(=0t)
0
0
0
cos
sin
vv
v
r
00
0OG
z
uuur
:
0- cosxv v =0 sinzv g t v = +
-
0 cos .v t=2 0 0
1sin2z g t v t z= + +
)()(: .
:=( )z h x=( )z g t=( )f t:-2
2
02 2
0
.2 cos
gz x tn x zv
= + +20,039 0,7 2z x x= + +
=0z:-3
2
0 0,039 0,7 2x= + +
.)(=20,45x m
:)-(M0G
0 0cM ppM cG ppGE E E E+ = +
0
2 2
0
1 1
2 2M Gm v m g h m v mgh+ = +
( ) ( )0
22 2
0 2 13,7 2 9,8 2 15 /M G Mv v g h h m s= + = + =
.vv:
))3
-1
-2 .=N Z)())-3
(
:
:+
14:( )14) 14 06 7 1C N e +
ar
0vr
vr
OGuuur
Oxuur
0 xdv
dt= 0 cosv 0 cosv 0 cos .x v t=
Ozuur
dv
gdt
= 0 sinv 0 sing t v +2
0 0
1sin .
2z g t v t z= + +
16
7N14
6C12
5B14
5B
12
7N
13
7N
11
6 C
8
5B
+
0x
z
d vdt
d v
dt
=
=
P
r
z
x
r
0vr
0
G
O
0G
2h m=
z
x
7/25/2019 Bac2011_M1
3/5
3
))3,5
)1S-1 : (1 1, , ,P f R Trr r r
)2S : (2 2,P Tr r
:)-2
)1S : (1 1 1P f R T m a+ + + =rr r r
r
:1 1 1sinP f T m a + =)1(
)2S : (2 2 2P T m a+ =r r
r
:2 2 2P T m a =)2(
1 2T T=)1()2(:
( )2 2 12
1 2 1 2
sing m md x fa
m m m mdt
= =
+ +)3(
) .) .0v=0x=)A=0t)
2
2d x ad t
dx= a t Cd t
.=0C+ =
21 '2
x a t C= +' 0C =( )2 1 2
1 2 1 2
sin1
2
g m m ft
m m m m
=
+ +
:
: :2
0 0
1
2a t v t x= + +
)=)0t=:0v=0x( )2 1 2
1 2 1 2
sin1
2
g m m ft
m m m m
=
+ +
))1)-32
x b t=
b :.
( )2 1 21 2 1 2
sin1
2
g m m fx t
m m m m
=
+ + .()1
(1
0,52
b= =1
2b a=21 /a m s=
:))3)
( )( )
( )( )2 1 1 2
1 2
sin 9,8 0,6 0,8 0,51 1,4 0,56
1,4
g m mf a m m N
m m
= + = =
+
)2(( )2 2 2 0,6 9,8 1 5,3T T P m a N = = =
))4
:)-1 )(
(( ) ( )d q t
i tdt
=( ) ( )Cq t C u t ( )= ( )Cdu t
i t Cdt
=
))-2 ) ( )R Cu t u t E + =
( )( )C C
du tRC u t E
dt= +
( ) ( )1 C Cdu t u t Adt
+ =
)6
1 200 250 10 0,05RC s = = =9A E V= =
1S
2S
1P
r
2Pr
fr
Rr
1T
r
2Tr
1 2
EC
R
R
0
K
e
i
7/25/2019 Bac2011_M1
4/5
4
(
( )( )1
C
C
du tE u t
dt =
:[ ] [ ]
[ ] [ ]1
UU
T =.
] ] [ ]1 T 1= .
1: .63%
1)-3 0,63 0,63 9 5,7Cu E V= = =
1 0,05s ..=
(t ( ) 0,99Cu t E=0,25t s =
15t
:
(
.) ) ( ) ( ) 0R R Cu t u t u t + + =
( )( )2 0C C
du tRC u t
dt+ =
( )( )2 0
C
C
du tu t
dt + =
)6
2 2 2 200 250 10 0,1RC s = = =
2 12 =
.
(
:
( )0 ; 9V( )2 ; 0,37E( )25 ; 0,01E
( )Cu V
( )t s
3,3
0,1
9
0,5
:
1,5V
1cm
9E V=.
...
0,1
1,5
( )Cu V
( )t s
5,7
0,05
9
t
7/25/2019 Bac2011_M1
5/5
5
))3,5
)-1: (-1
)-2()-2
:)2 2/ // /Zn Zn Cu Cu+ +
3-
2 2Zn Zn e+ = +)(
2 -+ 2Cu e Cu+ =)
(
( ) ( ) ( ) ( )2 2
aq
s aq sZn Cu Zn Cu+ ++ = +)(
)-3: (-4
5-(
2
2
1
11
i
ri
i
Zn
Q Cu
+
+
= = =
)(>riQ K
)
2 2Zn Cu Zn Cu+ ++ = +
0Cu
nCVCVZn
n0t=
2xCun x+CV x+CV xZnn xt
t 2x Q I t=
2I t x F =40,76 2 60
4,7 102 2 96500
I tx mol
F
= = =
:
:I t
xzF
=
.=2z
-6
)
-4(
2 2
4,Cu SO+
2 2
4,Zn SO+
CuZn
-1
-2
2 2
4,Cu SO+
2 2
4,Zn SO+
CuZn
V +-
+-
1iE
2iE
eW
-3
K+
24SO
2
Cu +
2Zn +
24SO
Cu Zn 3
NO
2e
I
2e
2Zn +
Zn 2e
Cu
-4