Bai Tap Vat Lieu Hoc

Embed Size (px)

Citation preview

  • 8/13/2019 Bai Tap Vat Lieu Hoc

    1/3

    1. Tnh ThTch v bn knh nguyn tMg bit rng khi lng ring ca Mg l 1,74g/cm khi vthtch cc qucu Mg chim 74% thtch ca mng tinh th.

    2. ng kt tinh theo kiu mng lp phung tm din, hng smng a=0.361nm ; Khi lngring ca Cu l 8.290g/cm khi; Nguyn tkhi ca Cu l 63.54. Xc nh sAvogadr

    3. Nhm kt tinh theo kiu mng lp phng tm din , c d=2.7g/ cm khi.Xc nh hng smng a ca tbo c bn ca nhm, t tnh bn knh nguyn tNhm

    4. bn knh nguyn tca Cban l 1.25 A (angdrong) kt tinh theo kiu lc phng .a) Xc nh hng smng a,c?b) Kim tra li nu d thc nghim ca coban l d=8.90g/ cm khi

    5. FeO c cu trc mng tinh thlp phng tm din kiu NaCl vi hng smng l a =0.430 nm . Tnh d ca FeO

    6. Thori kt tinh theo cu trc lp phung tm khi, hng smng a=4,11Aa) Xc nh bn knh ca Nguyn tThori

    b) Xc nh d ca thori . Bit M ca Thori = 232g/mol2. bi 2: khi lng ca Cu trong 1 mng c sl

    m=D.V= 8.29.(3.61*10^-8)=390*10^-24

    khoi luong cua 1 nguyen tu~ 9.75* 10^-23

    so N la 63.54/(9.75*10^-23)=6,5*10^23 ( de co sai ko nhi~???)

    bi 6:a)vi thori kt tinh theo kiu lp phng tm khi nn bn knh cua Thori R=(a*cn 3)/4=1.78A

    b)khoi luong cua Thori trong 1 mng c sl: 2*232*1.6605*10^-24 =7.705*10^-22 (g)d=m/v= 7.705*10^-22/(1.78*10^-8)3 =136.6g/cm^3

    3. bi 1 : Thtch ca mng tinh th:

    thtch ca cc qucu Mg :

    thtch ca nguyn tMg :

    bn knh ca nguyn tMg :4. 1. St alpha kt tinh theo mng lp phng tm khi.

    Xc nh bn knh ca nguyn tFe trong st alpha bit ttrng ca n bng 7,86.Cho Fe = 55,8 g/mol.

    2. Bn knh ca nguyn tNa bng 0,190 nm.Tnh ttrng ca Na kim loi (mng lp phng tm khi).Cho Na = 23,0 g/mol.

    3. Cu kim loi kt tinh theo mng lp phng tm din.Ttrng ca n bng 8,96. Tnh bn knh nguyn tca Cu.Cu = 63,5.

  • 8/13/2019 Bai Tap Vat Lieu Hoc

    2/3

    4. Cho thng smng tinh thca 2 dng th hnh ca Fe:- Fe alpha: lp phng tm khi; a = 0,286 nm.- Fe gamma: lp phng tm din; a = 0,356 nm.Tnh bn knh nguyn tv ttrng ca Fe trong mi trng hp.Fe = 55,8 g/mol.

    5. Mg kt tinh theo mng lc phng cht kht. Bit a = b = 0,320 nm.

    Tnh c.Tkt quthu c hy tnh tkhi ca Mg.Mg = 24,3 g/mol.

    6. Ti kt tinh theo mng lc phng cht kht.a) M ttbo n vca Ti.b) Tnh bn knh nguyn tca Ti, bit khi lng ring ca Ti bng 4,51 g/cm3Ti = 47,90 g/mol.

    7. Ttrng ca NaCl bng 2,165.Tnh tng bn knh ca 2 ion Na+ v Cl-MNaCl = 58,44 g/mol.

    8. Trong tinh thCaF2 cc ion Ca2+ nm trn mt mng lp phng tm din,cn cc ion F- chim tt ccc ltrng tdin.Bn knh ca cc ion Ca2+ v F- tng tng bng 0,099 v 0,133 nm.

    Tnh:- Thng smng a.- c kht p.- Ttrng ca CaF2MCaF2 = 78 g/mol.

    9. Trong kiu cu trc blend ca ZnS cc ion S2- nm trn mt mng lp phng tm din,cn cc ion Zn2+ chim mt na sltrng tdin theo 4 gc cho nhau ca tbo n v.Tnh tsnhnht ca r+/r-10. Bn knh nguyn tca C r = 0,077 nm.Tnh ttrng v c kht ca kim cng. C = 12,01 g/mol.11. FeO c cu trc kiu NaCl vi a = 0,430 nm.Gi trny c ph hp vi cc bn knh ion: r(Fe2+) = 0,075 nm; r(O2-) = 0,140 nm?12. Cu2O kt tinh theo mng lp phng

    trong cc ion O2- to thnh mt mng lp phng tm khi,cn cc ion Cu2+ nm im gia ca 4/8 na ng cho ca hnh lp phng.Xc nh:- Kiu phi tr v sphi tr ca cc ion.- Sphn tCu2O trong 1 tbo.- Thng sa ca tbo nu khi lng ring l 6,00 g/cm313. Dng th hnh cristobalit ca SiO2 c cu trc nh sau:Cc nguyn tSi sp xp cc vtr ging nh cc nguyn tC trong kim cngv gia 2 nguyn tSi l mt nguyn tO.- Vcu trc ca cristobalit.- Xc nh sphi tr ca Si v O.- Xc nh thng sa bit khi lng ring l 2,32 g/cm3MSiO2 = 60,1 g/mol.

    14. Xc nh nng lng mng li tinh thca NaCl, bit (kJ/mol):delta H (NaCl) = -411,2;

    delta Ho (th Na) = 107,3;

    delta Ho (pl Cl2) = 240;

    delta Ho (ionh Na) = 496;

    delta Ho (al Cl) = -349.

    15. Mt mu oxit st (II) FexO iu chtrong phng th nghim c tkhi 5,71 g/cm3.Bit rng oxit st (II) c cu trc kiu NaCl.Gc teta ca phn xbc nht thmt 200 bng 9,56o khi dng bc xKalpha ca Mo vi lamda

  • 8/13/2019 Bai Tap Vat Lieu Hoc

    3/3

    l 71,07 pm.

    Xc nh:- thng sca mng tinh th- Gi trca x trong FexO- TlFe2+ v Fe3+ trong oxit- Cng thc ha hc chr ha trca st trong hp cht

    5.Tbi 1 n bi 6 bn ch CT sauttrng = M*Z/Na*VZ l smt 1 mng, Na l savogadro, M l khi lng phn t, V l thtch 1V 3 CT chng minh c kht ca lp phng tm din, tm khi v lc phng tthng smng...(mnh post vo ln trong 4rum)Tcu 7 ngoi CT : ttrng = M*Z/Na*V p dng cc thng smng sau7/ Tnh tng bn knh da vo thng smng a=2(R+r)8/ thng smng CaF2 = 4cn3/3(R+r)9/ Cu trc blend th 0,225