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7/26/2019 Calcul cofraplus60 2xD=3.8 m
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Date :
Project :
Customer :
Architect :
Engineering office :
Product :
Building codes :
Author :
I . Project data
Country : Romania
Composite slab : Continuous spans Concrete : Normal concrete
Span: Type: NC25/30
n = 2 m c = 2450 kg/m
L1 = 3.8 m fck = 25 MPa
L2 = 3.8 m fctm = 2.6 MPa
ECM = 31000 MPa
Slab depth: a = 0.85
ht = 150 mmLimit of deflection: Steel deck : Cofraplus 60
f/L = 1 / 300 fy = 350 MPa
Fire resistance: Ea = 210000 MPa
RF = 60 min ts = 0.75 mm
h = 58 mm
Charges bbf = 62 mm
Permanent loads (supplementary): bd = 207 mm
gper = 0.00 kN/m buf = 106 mm
Live load: bop = 101 mm
q = 1.50 kN/m gs = 8.5 kg/m
Ap = 1029 mm
Reinforcement bars zcg = 33.3 mm
fya = 300 MPa Ibr = 55.1 cm4
Upper reinforcement: Ieff = 42.6 cm4
d1 = 0 mm Mrd,+ = 4.3 kNm/m
a1 = 0 mm Mrd,- = 4.3 kNm/m
e1 = 0 mm Rw,Ex = 23.5 kN/m
Reinforcement on support: Rw,C = 25.0 kN/m
d2 = 10 mm Mpa = 7.7 kNm/m
a2 = 100 mm zpl = 39.55 mm
e2 = 0 mm m = 230.09 N/mm
Lower reinforcement: k = -0.062 N/mm
d = 0 mm/rib RD = 0.1 MPa
e = 0 mm
Construction stage Hyperstatic
Safety factors f / L = 1 / 180
gM = 1.00 Steel sheet Props : YES
gsb = 1.15 Reinforcement Support width:
gc = 1.50 Concrete Ss,Ex = 50 mm
gvs = 1.25 Shearing Ss,C = 100 mm
g0 = 1.35 Permanent load Number of props:
gq = 1.50 Live load n1 = 1
Y1 = 0.50 Fire n2 = 1
kr = 0.20 Moment redist.
Cofraplus 60
Eurocodes
Diaconescu Razvan
Calculation note
10 March 2016
7/26/2019 Calcul cofraplus60 2xD=3.8 m
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II. Longitudinal section and cross section
III. Construction stage
Steel deck : Hyperstatic
Props : YES
Dead load of steel deck and concrete:
g = 2.90 kN/m
1. Deflection checking
d = 2.14 mm 15 = 10% ht
10.56 = L / 180
The ponding effect is ignored.
2. Ultimate limit states
* The loads to be taken into consideration during the conreting operation are the following:
Dead load of the steel deck and of the concrete:
g = 2.90 kN/m
Construction loads during casting of conrete (according to EN 1991-1-6):
qm = 0.75 kN/m
* Calculations of bending moments and support reactions
MEd,+ = 1.40 kNm MEd,- = 1.95 kNm
REd,Ex = 3.77 kN REd,C = 10.95 kN
* Checking of the resistance:
MEd,+/ MRd,+ = 0.32 1 OK MEd,-/ MRd,- = 0.45 1 OK
REd,Ex/ RRd,Ex = 0.16 1 OK REd,C / RRd,C = 0.44 1 OK
MEd,-/MRd,- + REd,C/RRd,C = 0.89 1,25 OK
IV. Verification of the composite deck slab
1. Ultimate limit states
* Three following criteria must be verified to ensure that no ultimat limit state is reached:
Bending resistance
Longitudinal shear
Vertical shear
* Calculation of the maximum design bending moments and vertical shears:
MEd,+ = 7.78 kNm MEd,- = 8.91 kNm
VEd,Ex = 9.80 kNm VEd,C = 14.06 kN
20 %With moment distribution of
cs ggg
cponding gg d7.0
areaworkingtheoutside0.75kN/m
mareaworkingtheinside1.5kN/m)thanmorenotand0.75kN/mthanless(not 3310 cm
g%q
L1 L2
L1/3 L2/3
7/26/2019 Calcul cofraplus60 2xD=3.8 m
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a. Sagging bending moment
Position of neutral axis:
Hypothesis: The neutral axis is in the concrete slab and above the steel deck.
Fs = 360150 N
Frib = 0 N
xpl = 25 mm 92 = hc
Moment of resistance:
Mpl,Rd,+ = 37.45 kNm 7.78 OK
b. Hogging bending moment
Hypothesis: the neutral axis is in the steel deck.
F1 = 0 N
F2 = 204886 N
x = 37 mm 58 = h
Mpl,Rd,- = 26.97 kNm 8.91 OK
c. Longitudinal shear
* m-k method This method is not used in this calculation
Shear length:
Ls = 0 mm
The maximum design vertical shear should not exceed the design shear resistance:
Vl,Rd = 0.00 kN VEd,Ex
* Partial connexion method
u,Rd = 0.10 MPa
Fs = 360.15 kN
In order to develop fully plastic moment, the distance of the cross-section being considered to the nearest support:
Lsf = 3602 mm
For fully plastic moment section:
xsr = 0 mm
xf = 25 mm
)2/2(2)2/1(1,,
/)/1000(85.0
/
/
0
21
22
11
plxethFplxethFRdplM
cdck
saya
saya
bbf
FFx
AfF
AfF
g
g
g
)(, kbL
AmbdV
s
p
pRdl
Rdu
ssf
b
FL
,
Fs
Fsr
Ncr= Fsr
Ncf= Fs
spanscontinuousFor
spansingleFor
4/9.0
4/
L
LLs
cb
ckf
ribF
sF
plx
saribA
yaf
ribF
spAyfsF
g
g
g
/85.0
/
/
)2/()2/(,, pl
xrib
et
hrib
Fpl
xp
ds
FRdpl
M
cck
sf
cck
rib
sr
bf
Fx
bf
Fx
g
g
/85.0
/85.0
7/26/2019 Calcul cofraplus60 2xD=3.8 m
4/7
For a distance Lx< Lsf, the connexion is partial and expressed by hand the moment of resistance by M Rd:
Mbr = 0.00 kNm Mcp = a*h + b*h
Mpa = 7.65 kNm a = -2.33
Mpr = 1.25Mpa(1-h) Mpa b = 39.78
h
Lx/Lsf Mpr Mcp MRd
0.00 7.65 0.00 7.65
0.11 7.65 4.17 11.82
0.21 7.54 8.29 15.84
0.32 6.54 12.36 18.89
0.42 5.53 16.37 21.90
0.53 4.52 20.34 24.86
0.63 3.51 24.25 27.76
0.74 2.50 28.11 30.610.84 1.49 31.92 33.41
0.95 0.48 35.68 36.16
1.06 0.00 37.45 37.45
OK
e. Vertical shear
* End support
The vertical shear resistance is determined according to EN 1994-1-1 and EN 1992-1-1 :
CRd,c = 0.12
1 = 0.020
h1 = 1.00
k = 2
4.25
MEd
0.00
3.28
5.67
-2.55
Lx
0
0.38
0.76
1.14
1.52
1.90
7.17
7.78
7.49
6.32
-7.283.80
1.30
3.42
2.28
2.663.04
-10
-5
0
5
10
15
20
25
30
35
40
0 0.5 1 1.5 2 2.5 3 3.5 4
M(
kNm)
Lx(m)
Moment of resistance Design moment
cf
c
sf
x
N
N
L
Lh
2/12/3
min
2/12/3
min
0
1
1
1
,,
01min01
3/1
11,
01min01
3/1
1,
,
03.0035.0
/
15.0
0.2/2001
2200/6.04.0
/15.0/18.0
)()100(
)()100(
lcklck
cEdcp
p
sl
p
c
cclRdccRd
pcplpcplckclRd
pcppcpckcRd
cRd
fkVfkV
AN
db
A
k
dk
CC
dbkvdbkfkC
dbkvdbkfkCV
h
gg
h
concretelightFor
concretenormalFor
s
cf
ppfsrcfccp
pa
s
cf
papr
srribtribbr
prcpbrRd
F
NeeexxhNZNM
MF
N
MM
xehFM
MMMM
hhh
h
)()5.0(
)1(25.1
)2/(
7/26/2019 Calcul cofraplus60 2xD=3.8 m
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k1 = 0.15
cp = 0
Vmin = 0.495
VRd,c = 40.62 kN 22.74
= 40.62 kN VEd,Ex OK
* Internal support
dp = 150 mm
1 = 0.013
k = 2Vrd,c = 45.58 kN 29.23
= 45.58 kN VEd,C OK
2. Serviceability limit states
a. Deflection control
Modular ratio steel - concrete (average value of the modulus for both long and short term effects):
n = 13.55
* Homogeneous section
xh = 66.95 mm
Ibh = 1.57E+07 mm4
* Cracked section
xf = 44.78 mm
Ibf = 9.93E+06 mm4
* Deflection checking
Average value of the second moment of area:
Ibm = 1.28E+07 mm4
Deflection:
f = 2.27 mm
f/L =1/ 1672 1/ 300 OK
b. Crack control
According to EN1992-1-1, the required minimum areas of reinforcement may be calculated as follows :
kc = 0.4
k = 0.65
As,min = 207.31 mm 119.60 mm
= 207.31 mm
As = 785.40 mm 207.31 OK
c. Vibration control
The frequency of the slab is calculated using the following fomulae
f0 = 10.34 Hz 5 OK
2
3/CM
a
CM
a
E
E
E
E
n
22
2323
2
)()(212212
)(2
hcotcophpp
p
h
pcpcch
ccbh
coppcc
cotcoppppcc
i
ii
h
xehAIxdAhxhnhb
nhbhx
nbh
nbhI
nAnAhbbh
ehnAdnAdhbh
b
A
zAx
22
3
2
)()(3
))((2()(
fcotcopfpp
f
bh
cotcoppcopcop
f
xehAIxdAn
bxI
b
ehAdAn
b
AAn
b
AAnx
2bfbh
bm
III
qqggm percs
Lm
bhIaE
f
5.0
Hz54
1000
20
cts
cteffctcss
AA
AkfkA
0013.0min,
,min,
onconstructiproppedfor
onconstructiunproppedfor
supportedsimplyasdesignedisspancontinuousif
004.0
002.0
min,
min,
cts
cts
AA
AA
7/26/2019 Calcul cofraplus60 2xD=3.8 m
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V. Fire resistance
1. Geometry of the steel deck (according to Figure 4.1 of EN 1994-1-2)
h2 = 58 mm 50h2100 OK
l1 = 101 mm 80l1155 OK
l2 = 62 mm 32l2132 OK
l3 = 106 mm 40l3115 OK
A = 4,727 mm/mm Concrete volume in the rib per m rib length
Lr = 184 mm/mm Exposed area of the rib per m rib length
A/Lr = 26 mm Rib geometry factor
F = 0.727 - View factor of the upper flange
a = 71 degrees Angle of the web / horizontal
b = 0.32 Radians Angle of the web / vertical
2. Fire resistance according to thermal insulation "I"
t1 = 118 min 60 OK
3. Integrity criterion "E"
For composite slabs the integrity criterion "E" is assumed to be satisfied (according to EN 1994-1-2).
4. Load bearing criterion "R"
a. Calculation of sagging moment resistance
Temperatures of the lower flange, web and upper flange of the steel decking:
Temperatures of the reinforcement bar in the rib :
Load bearing of each part of the slabs after 60 minutes :
Temperature ky,i Ai Zi Mi
(C) [-] (cm) (cm) (kNcm)
Lower flange
Web
Upper flange
Lower reinforcement
Concrete
Mfi,Rd,+ = kNm
b. Calculation of hogging moment resistance
Temperature ky,i Ai Zi Mi
(C) [-] (cm) (cm) (kNcm)
Upper reinforcement - -
Reinforcement on support - -
Concrete
Mfi,Rd,- = kNm
Fi
(kN)
Fi
(kN)Part of the slab
2
432
3
10
1FF bb
L
Ab
lbb
r
a
3213
5432
2
310
1111 with
1
uuuzlcc
L
Aczc
h
ucc
r
a a
7/26/2019 Calcul cofraplus60 2xD=3.8 m
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c. Fire resistance checking of composite slab
Applied load (according to EN 1991-1-2):
Y1,1 =
Pfi,Ed = kN/m
Verification of fire resistance according to EN 1992-1-2 (annex E):
Mfi,Ed,1 = kNm = Mfi,Rd OK
Mfi,Ed,2 = kNm = Mfi,Rd OK
0.35*Mfi,Ed,max = 0.00 kNm = Mfi,Rd,+ OK
1,1,1, kEdfi QGP Y
spanscontinuousFor
spansingleFor
2
8
,,
,,,,,,
,,
,
2
,
,,
Rdfi
eRdfiwRdfi
Rdfi
Rdfi
iEdfi
iEdfi
MMM
M
M
LPM
Mfi,Rd,-,w
Mfi,Rd,-,e
Mfi,Rd,+
Mfi,Ed