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8/7/2019 devoir en physique
1/3
-2-22/12/2010 . 2 :2
))))6666((((pH
. :pHS0AHc0=17,5mol.L
1.1,00mL.500mLV=S1c1
S1.c1.-12-AH.3-.4-pH-pHS1:pH=3,1.1
.5-
c1. AHS0.
:S2AHc2 = 5,0 103 mol.L1.
2 = 1,07 102 S.m1.HO.-
1-+ 3 2H OS2.
:= 4,1 103 S.m.mol1A
= 35 103
S.m.mol1
H O3+
2-2AHS2.
3-2
..1 ----IIII----))))8.58.58.58.5((((
:2102101889
...138
:81
Tl82
Pb83
Bi84
Po85
A t86
Rn
):4 ) 4,00152
m He u=9( ) 9,009984
m Be u=12( ) 11,996716
m C u=
1( ) 1,00860m n u=
210:210 / M g mol=:82,99792.10 /c m s=
23 16,022.10 N molA
=27
1 1,6605.10u kg
=
1-210.2-210.3-:"2101g166000"
:2102008210
.. .1-172000210.
1
0.5
0.75
0.5
0.5
1.5
0.25
1
0.5
0.25
1
0.5
1/3
HCOOHHCOOHHCOOHHCOOH 0,0720,0720,0720,072
CHCHCHCH3333COOHCOOHCOOHCOOH 0,0230,0230,0230,023
CHCHCHCH3333CHCHCHCH2222COOHCOOHCOOHCOOH 0,0180,0180,0180,018
8/7/2019 devoir en physique
2/3
21500.2-%99
.210:
2101934.100
:
9 4 14 2 0AZ Be He X n+ + 1-A
ZX
2-E..:24
23242411
Na:
23 1 2411 0 11
Na n Na+
1-2411
Na.
2-2411
Na2412
MgAZ
Y..
t=15h.24-34-Vt=0V0=10mL
C0=1024-3mol/L.
4-1-24t1=7h.4-2-t1. 4-3-t1V2=10mLn2=1,5.10
-8mol.V24.
----IIIIIIII----))))5.55.55.55.5((((--RC:
..
)(.2(C=10pF.)RC1(.R).
2
t
=.
RC.
1-uc 2-.3-Q.U=500V.
0.75
0.25
0.5
0.25
0.5
0.5
0.5
0.5
2.5
0.25
0.5
0.25
2/3
+
U
R
-1
8/7/2019 devoir en physique
3/3
4-NN)(.0,10t ms =.
4-1-R.
4-2-c
ut:c
Neu
C = e
.:RCRC--3-E=6V..t=0.
1-uc:du
c u Ecdt
+ =
2-.
3-:(1 )tu A ec
= A.
u-4
c
.
AB
0.25
2.5
0.5
0.25
0.5
0.5
3/3
-2
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