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8/9/2019 DEVOIR Surveill N1 (Complt)
1/7
1
12/7/ 2007 ( 2 30) . Hz100= S ( I
. 1t
1( . .T 2(
.v 3( . S 4(
. 1t ( . A (
.2
34
Ttt +=
423
Ttt += st 025,0
2= 5( :
. S cmSN 10=
cmSM 5,7=
N M )6 . S N M (
. NM ( . S N M (
N2 m2 7( . Hze 101= Hze 100= Hze 99= )8
II( a. )1
.L D )2 mD )3 a =5,1
. L
3-1: .
.
a
1 3-2: 2
. a
1 3-3:
3-4: .
).( ma
)(mmL
)10(2 rad 0,5 1,0 1,5 2,0 2,5
)10(1 14 ma
1 2 3 4 5
8/9/2019 DEVOIR Surveill N1 (Complt)
2/7
2
SBIRO Abdelkrim : 5: 7,5 :7,5 :
.nm : 3-5
( : 4
( mn. (2
640046,1
+=n
1.4( :
400 800 : ).( mn
.........=
Vn ........=
Rn . = 60A = 35i 2.4( . RD )
. VD )
. ( ///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
hPa1013 C20 )( 2CO
V
. )( 2COV
molm. :: )1 2( .
.R dt
dx P T )(tx
)( 2COV 3(
.)( 2CO
V 4(
5( . 6( .
KmolJR ./314,8= molgCaCOM /100)( 3 = :
8/9/2019 DEVOIR Surveill N1 (Complt)
3/7
3
Rponse1( .
.
------------------------------------------------------------------------------- :T )2
sT 01,0100
11===
cm5= 3( :
smHzmv /5100105.2
=== :
------------------------------------------------------------------------------- .v cmd 10
1=
1t ()4
. ssm
m
v
dt 02,0
/5
10102
1
1=
==
:1
1
t
dv = :
mcmSA 15,015 == :(
. ssm
m
v
SAt 03,0/5
15,0 === : A :
------------------------------------------------------------------------------- st 025,02 = (5
. Tt 5,22 = : 5,201,0
025,02==
s
s
T
t:
234
Ttt +=
8/9/2019 DEVOIR Surveill N1 (Complt)
4/7
4
sT
tt 0275,04
01,0025,0
423
=+=+= ) : :
Tt 75,22
= : 75,201,0
0275,02 ==Tt :
2+4/3 .
sT
tt 0325,02
01,00275,0
234 =+=+= ) :
Tt 25,32 = : 25,301,0
0325,02==
T
t:
3+4/1 .( //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
. 5,1=SM : 5,15
5,7
== cm
cmSM
6()
.2
3
=SM : 35,2
5,7
2
==cm
cmSM
1=k 2
)12(
+= KSM :
. 2=SM : 25
5,7==
cm
cmSN
-- ---- --- --- ---- ---- -- ---- --- --- ---- --- --- ---- ------------ -- ---- --- --- ---- --- --- ---------- ---- --- --- ---- --- --- ---- ---- -- ---- --- - . M S )
. NM : N S ---- ---- -- ---- --- --- ---- --- --- -------------- --- --- ---- --- --- ---- ---- -- ---- --- --- ---- --- --- ---- ---- -- ---- --- --- ---- --- --- ---- ----
-. cmYS 8,0max = : S (
. cmYM 8,0= : S M M S
. cmYN 8,0+= : S N N S
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
kgsm
mN
v
Tm 16,0
)/(25
22
22
=
=
=l
vm
Tv =
2 :
l
m
Tv = 7(:
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// . Hze 100= 8(
. Hze 99=
. Hze 101=
=========================================================================== . . (1 ( II
------- ---- --- --- ---- --- --- ---- ---- -- ---- --- --- ---- --- --- ---- ---- -- ---- --- --- ---- --- --- --------- -- ---- --- --- ---- --- --- ---
2(
8/9/2019 DEVOIR Surveill N1 (Complt)
5/7
5
3(3-:1
-- --- --- ---- ---- -- ---- --- --- ---- --- --- ---- ------ ---- -- ---- --- --- ---- --- --- ---------- ---- --- --- ---- --- --- ---- ---- -- ---- --- --- -- 3-2:
a
= 3-3
- --- --- ---- --- --- ---- ---- -- ---- --- --- ---- --- --- ---- ---- -- ---- --- --- ---- --- --- ---- ------ --- ---- --- --- ---------- ---
ak
1= )
1(a
f= 4: : 3-
. k : :3-5
nmmmmrad
aaa
k
AB
AB 50010500105,010)25(10)15,2(
)1
()1
()1
(
96
14
2
===
=
=
=
nm500= : /////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
47,101,046,1800
640046,1
640046,1
22=+=+=+=
R
Rn
(1( 4
5,104,046,1400
640046,1
640046,1
22=+=+=+=
V
Vn
400 800 : ).( mn
5,1=Vn 47,1=Rn
).( ma 100 50 33 25 20
)(mmL 15 30 45 60 75
)10(2 rad 0,5 1,0 1,5 2,0 2,5
)10(1 14 ma
1 2 3 4 5
8/9/2019 DEVOIR Surveill N1 (Complt)
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6
( (2:
===
23)39,0(sin)47,1
35sin(sin)
sin(sin
111
n
ir
n
ir
sinsin = rni sinsin =
=== 372360' rAr :
( = 8,42)47,1
1(sin
1
li :
lir
8/9/2019 DEVOIR Surveill N1 (Complt)
7/7
7
TRnVPcoco ... )()( 22 = 3(:
: )()( 2cot
nx =
P
TRxV
t
CO
..)(
)( 2= :
dt
Vcod
TRV
Pv
S
)(
..
2= :.
TR
coVPx t
.
)(. 2)( = :
dt
xd
V
vt
S
)(1 )(
= 4(
-------------------------------------------------------------------------------------------------------------
molx
xt
3max
)(105,2
22/1
== 5(
:
lmmPa
KKmolJmol
P
TRxV
t
CO 60106101013
293..314,8105,2.. 352
113)(
)( 2==
==
:2/1
t
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// :: )6
molmx
n co .5,22
max
)( 2==
:
3CaCO + +OH
32 +2Ca +
2CO + OH
23
)()( 22 conCan =+
max
2)( xCan =
+ :
SV
lmolmol
V
x
V
Can
SS
/05,01,0
105)(3
max
2
=
==
+
l
Bonne chance
SBIRO Abdelkrim (Lyce Agricole Oulad-Taima rgion dAgadir Maroc)
Pour toute observation contacter mon mail
sbiabdou@yahoo.fr
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