Comment montrer qu'une fonction est dérivable en un point ?

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  • 8/6/2019 Comment montrer qu'une fonction est drivable en un point ?

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    LhaboMrhvethfk

    ItbfmosotEkkecos

    bttp7//oxfs0ie

    tb.lroo.lr/

    Ifktror quuko lfkathfk ost mrhve`co ok uk pfhkt.

    Peppoc mo afurs

    Mstkhthfk

    Fk mht quo l ost mrhve`co ok e sh, ot soucoiokt sh, l(e+b) l(e)

    b

    emiot uko chihto stkho quekm b tokm vors>.

    Co kfi`ro ost ecfrs eppoc kfi`ro mrhv mo l ok e, ot kft l(e).

    Poierquo 7 Aotto mstkhthfk ost uthchso pfur rotrfuvor cos lfriucos mo mrhvethfks usuoccos. ^fur ifktror quuko

    lfkathfk ost mrhve`co ok pfhkt fk uthchsore pcutt ce mouxhio mstkhthfk.

    Mstkhthfk

    Fk mht quo lost mrhve`co ok e sh, ot soucoiokt sh, l(x) l(e)

    x e emiot uko chihto stkho quekmx tokm vors e 4 ecfrs 7

    chixe

    l(x) l(e)x e 9l

    (e)

    ItbfmoHc oxhsto moux aes euxquocs kfus sorfkt afklrfkts pfur mtorihkor ce mrhve`hcht. Meks tfus cos aes, hc leut afiiokaor

    per aecaucor co reppfrt mo ce mouxhio mstkhthfk, ot co iottro sfus uko lfrio mfkt ce chihto sore leahco mtorihkor.

    Oksuhto fk mhsthkjuo cos moux aes 7

    Ce chihto mu reppfrt tokm vors, ot meks ao aes ce lfkathfk kost pes mrhve`co ok e. Qh chi

    xe

    l(x) l(e)x e 9 chixe+

    l(x) l(e)x e 9 chixe

    l(x) l(e)x e , ecfrsl ost mrhve`co ok e.

    Oxorahao 5

    Qfht lce lfkathfk x |x0 5|. l ost-occo mrhve`co ok 5 6 Gusthstor ce rpfkso jrepbhquoiokt, puhs per aecauc.

    Oxorahao 0

    Qfht lce lfkathfk x x shk x.5. Gusthstor quol ost mrhve`co sur Y>4 +T ot aecaucor l(x) pfur tfut x mo aot hktorvecco.0. Mifktror quol ost mrhve`co ok >, ot prahsor l(>).

    Oxorahao 5

    Alemiot ok5moux moih-tekjoktos mo pokto 0 jeuaboot +0 mrfhto. Qh l ost teht mrhve`co ok 5, Al emiot-treht uko souco tekjokto. Fk pout ecfrs afkacuro quo l

    kost pes mrhve`co ok 5.^fur tfut x T5 4 +T 7 x0 5 >, mfka l(x) 9x0 5.Fr ce lfkathfk x x0 5 ost mrhve`co sur P, mo mrh-vox

    0x. lafkahmo surT54 +

    T evoa x

    x0

    5,

    mfka 7 chix5+

    l(x) l(5)x 5 9l

    (5+) 9 0.

    Mo lefk ekecfjuo, pfur tfut x T5 4 5Y, x0 5 >,mfka l(x) 9(x0 5) 9 5 x0. lafkahmo sur T5 4 5Yevoa x 5 x0, quh e pfur kfi`ro mrhv0 ok 5,mfka 7 chi

    x5

    l(x) l(5)x 5 9l

    (5) 9 0.

    Fk e mfka 7 chix5

    l(x) l(5)x

    5 9 chi

    x5+

    l(x) l(5)x

    5 , ao

    quh prfuvo quo lkost pes mrhve`co ok 5.

    Oxorahao 0

    5. x x ost mstkho sur P+ ot mrhve`co sur P+4meutro pert, ce lfkathfk shkus ost mstkho ot mrhve`co sur

    P. lmfka ost mrhve`co sur P+ afiio prfmuht mo lfka-

    thfks x x ot x shk x mrhve`cos sur P+.^fur tfut x P+, l(x) 9

    shk x

    0

    x+

    x afs x.

    0. ^fur tfut x ;> 7

    l(x)

    l(>)

    x > 9

    x shk x

    x 9 x shk x

    x .

    Fr fk seht quo chix>

    x9 > ot chi

    x>

    shk x

    x 9 5. Ehksh,

    chix>

    l(x) l(>)x > 9 >. Fr l

    (x) 9

    x

    shk x

    0x + afs x

    sfht chix>

    l(x) 9 chix>

    x

    5

    0+ >

    9 >.

    Fk e ecfrs l(>) 9 chix>

    l(x) l(>)x > , ao quh prfuvo per

    mstkhthfk quo l ost mrhve`co ok > ot l(>) 9 >.

    Ettokthfk 7 Hah fk ktumho pes ce chihto jeuabo aer

    occo koxhsto pes ! l ost mrhve`co ukhquoiokt pfur cos

    rocs strhatoiokt pfshthls, mfka fk ko seht rhok mo ao quh

    so pesso jeuabo mo >.