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DNA coby polyelektrolyt: Manningova teorie kondenzace protiiontů
Manning, G. S. (1978). "The molecular theory of polyelectrolyte solutions with aplications to the electrostatic properties of polynulceotides." Quart. Rev. Biophys. 11: 179-246.
Jiří Kozelka Université Paris DescartesLaboratoire de Chimie et Biochimie Pharmacologiques et ToxicologiquesUMR CNRS 860145 rue des Saints-Pères75270 Paris FRANCE******Masaryk University of BrnoInstitute of Condensed Matter PhysicsFaculty of ScienceKotlářská 261137 Brno CZECH REPUBLICTel. +420 549 49 4048Port. +420 720 379 379
DNA double helix
Double-stranded DNA can be considered as a linear long rod composed of segments, each carrying one unit charge. The segments repel each other. The repulsion is diminished if positively charged counter-ions associate with the DNA surface.
__
_
__
_
__
__
__
1 segment: charge -1e
b = 1.7 Å
distance between segments b defines the charge density of the polymerb-1
+
+
++
+
+
+
+
+
+
+
+
At each segment, a fraction of positive counterions „condenses“ within a volume VP
G/ = 0
VP
1 equation2 unknowns
Univalent salt in water (e.g., NaCl)
DNA double helix__
_
__
_
__
__
__
G(, VP ) / = 0
The charge of 1 segment is reduced to (-1+)e
Gain in enthalpy H, since repulsion between segments diminishedLoss in entropy S, since order increases
Nature will „choose“ such a fraction, that G = H – TS minimal
qnet qnet qnet qnet qnet qnet qnet qnet
Calculation of the electrostatic repulsion term Gel
Phosphate N°: 1 2 3……………..s………………………np
Each pair contributes:
b
|i-j| = 1: number of pairs = np-1|i-j| = 2: number of pairs = np-2
2b
.
.|i-j| = s: number of pairs = np-s
|i-j| > s: interaction negligible
if np>> s
≈ np
≈ np
≈ np
Gij≈ 0
Charge:
rD = „Debye screening length“proportional to c-1/2
c: concentration of univalent salt
qnet = qe(1- )D
i j b2 2re e
ij
k q (1- )ΔG e
ε i- b
θ
j
D
i-j b2 2 sAV e e r
eli-j
p
=1
L k q (1- ) 1ΔG = e
ε
n θ
b i-j
All pairs contribute:
Coulomb Debye-Hückelscreening factor
efekt vody
efekt soli
D D D D
i-j b b 2b 3bsr r r r
i-j =1
1 1 1e = e + e + e +...
i-j 2 3
Simplifying the sum over pairwise electrostatic repulsion terms
D
i-j b2 2 sp AV e e r
eli-j =1
n L k q (1-θ) 1ΔG = e
εb i-j
Looks like a Taylor series….
f(x) =
Cvičení 1: odvoďte Taylorův rozvoj pro funkci f(x)=ln(1+x)(vyžadováno je řešení, nikoliv jen výsledek)
Taylorův rozvoj :
List of Taylor series of some common functions
http://en.wikipedia.org/wiki/Taylor_series
Simplifying the sum over pairwise electrostatic repulsion terms
D
i-j b2 2 sp AV e e r
eli-j =1
n L k q (1-θ) 1ΔG = e
εb i-j
D D D D
- i-jb -b -2b -3bsr r r r
i-j=1
1 1 1e = e + e + e +...
i-j 2 3
xe = 1+x for x<<1
2 3 4x x x x
e = 1+ x + + + +...2 6 24
Cvičení 2: vypočtěte sumu
=
Cvičení 3: zjednoduštesumu (rD>>b)
D D D D
i-j b b 2b 3bsr r r r
i-j =1 D
1 1 1 be = e + e + e +...= -ln( )
i-j 2 3 r
Simplifying the sum over pairwise electrostatic repulsion terms
Sum has become a simplelogarithmic term!D
i-j b2 2 sp AV e e r
eli-j =1
n L k q (1-θ) 1ΔG = e
εb i-j
2
Del p
Del
bΔG = -ξRTn (1-θ) ln( )
bln( ) < 0; ΔG
rr0
is dimensionless charge density2
e ek q 1with ξ=
εb kT
2 2p AV e e
elD
n L k q (1-θ) bΔG =- ln( )
εb r
Cvičení 4: Vypočtěte pro dvojšroubovicovou DNA (b = 1.7 Å) při 25 °C
2e ek q 1
with ξ=εb kT
k = 1.38x10-23 J.K-1 T = 298 K ke = 9.0x109 Nm2C-2 = 78 qe = 1.60x10-19 C
+
+
++
+
+
+
+
+
+
+
+
A fraction of positive counterions „condenses“ within a volume VP
VP
Loss in entropy S, since order increases
DNA double helix__
_
__
_
__
__
__
cbulk
clocal= nP(nPVP)-1 = VP-1
cbulk = c = concentration [mol/L] of univalent salt KNOWN
Let‘s minimize the total free energy with respect to
Mixing entropy term dependent on
Vp UNKNOWN → HOPELESS CALCULATION???
VP [L/mol] = volume to which the counterions/phosphate are confined
(ΔG)/ θ = 0
i.e., loss in entropy when the fraction of counterions associates with each segment
)c
θVRTln(θn)
cc
RTln(θnG1
PP
bulk
localPmix
number of moles of couterions that is confined from cbulk to clocal
)]c
θVln(θ)
r
bln(θ)ξ(1[RTnΔGΔGΔG
1P
D
2Pmixel
Cvičení 5: Vypočtěte první derivaci následují funkce podle x :(řešení a výsledek)
)2x1
1(ln)(
xf
Minimizing total free energy
-3
0D 2
AV e
ε εRT 10r m =
2(L q ) c
2e ek q 1
b =εξ kT
From Debye-Hückel Theory of electrolytes
)]c
θVln(θ)
r
bln(θ)ξ(1[RTnΔGΔGΔG
1P
D
2Pmixel
)]c
θVln(1)
rb
ln(θ)(1[2RTn
)]c
θVln(1
θ1
θ)rb
ln((-1)θ)(12[RTn
1P
DP
1P
DP
δθ
δ(ΔG)Cvičení 6: vypočtěte derivaci. Naznačte postup výpočtu.
Dependence of Gel on c Dependence of Gmix on c
-3
0D 2
AV e
ε εRT 10r m =
2(L q ) c
2e ek q 1
b =εξ kT
1 12 2 2 2 6e e AV e e e AV2 2
-3 2 3 -3D 0 AV 0
k q 2L q c 2k q L cb 1( ) ( )
r εξ kT ε εL kT 10 ξ ε (εkT) 10
0)θV
cln(1]
10kT)(εξcLq2k
ln[21
θ)(12 1P
330
2AV
6e
2e
0)θV
cln(1]
10kT)(εξcLq2k
ln[θ)(1 1P
330
2AV
6e
2e
0)]c
θVln(1)
rb
ln(θ)(1[2RTnδθ
δ(ΔG) 1P
DP
k Boltzmann‘s constant dimensionless charge density of polymerke electrostatic constant c concentration of univalent electrolyteqe electron charge dielectric coefficient of electrolyte vacuum permittivity T absolute temperatureLAV Avogadro‘s number fraction of counterions condensed
VP volume to which counerions condense
knowns
unknowns
We want to know at the low concentrationlimit, c→0
(1- ) - 1 ξ θ = 0
-1 = 1 ξ-θ
→Singular ln c terms
must vanish!
ln c↓
-∞
ln c↓
-∞
Now we have got a second
equation!
0)θV
cln(1]
10kT)(εξcLq2k
ln[θ)(1 1P
330
2AV
6e
2e
We want to know at the low concentrationlimit, c→0
(1- ) - 1 ξ θ = 0
-1 = 1 ξ-θDNA in water:
= θ4.2 = 0.76
→Singular ln c terms
must vanish!
ln c↓
-∞
ln c↓
-∞
Now we have got a second
equation!
0)θV
cln(1]
10kT)(εξcLq2k
ln[θ)(1 1P
330
2AV
6e
2e
1
-1θ
no association of counterions
association of counterions
76% of the negative charge of the phosphates
is neutralized by condensed counterions!
k = 1.38x10-23 J.K-1 = 8.85x10-12 C2N-1m-2 DNA in water at 25°Cke = 9.0x109 Nm2C-2 LAV = 6.02x1023 mole-1 = 4.2qe = 1.60x10-19 C e = 2.718 =78
T = 298 K= 0.76
(1- ) - 1 ξ θ = 0
Now we can determine VP, the volume to which the θ counterions/nucleotide condense in double-stranded DNA
0)θV
cln(1]
10kT)(εξcLq2k
ln[θ)(1 1P
330
2AV
6e
2e
1
mole/m6.46x10L/mole646.010kT)(εξ
eθLq2kV 34-
330
2AV
6e
2e
P
= 6.46x1026LAV-1 Å3/nucleotide = 1073 Å3/nucleotide
base of natural logarithms
-1 = 1 ξ-θ
Counterion Condensation Theory: Manning, G. S. (1978) Quart. Rev. Biophys. 11: 179-246
20 Å
7 Å
7 Å
The volume to which the condensed univalent counter-cationsare confined, VP
Per mole: 646 cm3
Per nucleotide: 1073 Å3
This corresponds to a layer of ~7 Å around the DNA double-helix(which corresponds ~to a cylinder with a diameter of 20 Å)
Experimental and theoretical results supporting the Counterion Condensation Theory
1. Titration of Carboxymethylcellulose (CMC) with different hydroxides monitored by ultrasonic absorption
CMC
Titration with XOH; X = Na, K, Li, N(CH3)4…….
Upon titration, the COOH groups are successively deprotonated, become COO-, and the negative charge density increases. This modifies the structure of the water layer at the surface of the polymer, which can be monitored by measuring the absorption of ultrasound. If there is no association of cations with the polyanion, the structure of the water layer should be independent of the cation.
O
OH
OH
O
OHO
OO
OH
OH
O
OHO
O
OH
OH
O
OHO
O
O
O
OH
OH
O
OHO
+ OH-
O-
O+ H2O
< 1: no difference between the various hydroxides no association between the counterions and the polymer
> 1: great differences between the various hydroxides association between the counterions and the polymer, as predicted by the Manning theory
R. Zana et al., J. Chim. Phys, 68, 1258-1266 (1971)
Radial distribution of Na+ counterions around a DNA duplex 12 base-pairs long,from a molecular dynamics simulation (Yang et al., J. Am. Chem. Soc. 1997, 119, 59-69). The calculation predicts 82% of the phosphate charge to be neutralized,with cations moving within a radius of 15 Å from the helix axis. Manning theorypredicts 76% of cations within 17 Å from the helix axis.
2. Molecular dynamics simulations of a solvated DNA duplex
[Å]
% phosphatecharge
20 Å
7 Å
7 Å
-1 θ = 1- ξ
= fraction of monovalent cations predicted by Counterion Condensation Theory to condense on each unit charge of the poly-anion
If then a fraction of 1-ξ-1 counterions condense at each unit charge
If , there is no counterion condensation.
duplex DNA in H2O at 298 K: = 4.2 single-stranded DNA: = 2.1
In a diluted solution of counterions, is concentration-independent!
Remember:
http://matematika-online-a.kvalitne.cz/derivace-funkce.htm