MATH 27 UNIT 4.3

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    4.3 AREA

    ofPOLAR

    REGIONS 

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    Area of a sector 

     Area of a sectorof a circle:

    where is in

    radians

    θ

    1

    r  A=

    θ

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    Area of a polar region

    Suppose for   0 θf r   

    ]

     

    θd f  A   2 2 

    1

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    Suppose

    for 

      0 θgf  

    ]

     

    ]

     

     

    θ

    d gf  A   2 2 2 

    1

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    Example. Setup the definite inte!ral

    that sol"es for the area of the shaded

    re!ion#

    θcosr  $ $  

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    Solution:

     

    ]

     

    θd f  A   2 2 

    1

    [ ]

      θd cos   2 $ $ 2 

    1

    π2 

    %$ π

     

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    Example. Setup the definite inte!ral

    that sol"es for the area of the shaded

    re!ion#

    θ2 cosr  

    &

    π

    θ

     

    1 A

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    Solution:

     

    ]

     

    θd f  A  2 

    1 2 

    1

    [ ]

    θd cos   2 2 2 

    1

    π

    1

     A A=

    =

    1( 

    '   π

    π

    =

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    Example. Setup the definite inte!ral

    that sol"es for the area of the shaded

    re!ion#

    2 r 

    π

    θ

    cosr  2 2  

    2  A 1 A

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    Solution:

     

    2 12 

      A A A 

    [ ]

     

    θd cos A

      2 

    1  2 2 

    1

    [ ]

    θd  A   2 2    2 2 1

    π

    π

    π

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    Example. Setup the definite inte!ral

    that sol"es for the area of the shaded

    re!ion#

    2 r 

    1 A

    θ

    cosr  2 2  

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    Solution:

     

     

    θd cos  2 2 2 2 2 2 

    1

    12  A A=

    π

    π

     

    ]

     

    ]

     

     

    θd gf  A

      2 2 

    1 2 

    1

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    Example. Setup the definite inte!ral

    that sol"es for the area of the shaded

    re!ion#

    1r 

    θ2 sinr  

    1 A

    θ

     

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    Example. Setup the definite inte!ral

    that sol"es for the area of the shaded

    re!ion#

    θcosr    2 1  

    )r )

    2 πθ

     

    2  A

    1 A

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    Solution:

     

     

    θd cos A   2 2 1   2 1) 2 1

     

    2 12    A A A 

    2 π

    [ ]

    θd  A   2 2    ) 2 

    1  π

    2 π

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    END