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7/25/2019 Bac2011_M2
1/5
1
- -2011
))3,5
):-1 ) ( )R bu t u t E + =
( ) ( ) ( )di t
Ri t ri t L E
dt
+ + =
( ) ( ) ( )di t
R r i t L Edt
L= + +( ) ( )
( )di t R r E
i tdt L L
++ =
( ) 1R r
L
+=
( ) ( )di t i t Edt L
+ =
2-( ) tdi t A
edt
=t t
A A A Ee e
L
+ =
A E
L=
EA
R r=
+
t:: =i A 0
EA I
R r= =
+
3-L
R r=
+[ ].
[ ] [ ][ ]
T UL
I= [ ]
[ ][ ]
UR r
I+ =
[ ] [ ][ ]
[ ][ ][ ]
[ ]T U
TU
AA
= =
4-( 00,63 0,63 180 113,4i I mA= = =0,17ms=)(
)0
ER r
I= +
0
945 5
0,18
Er R
I= = =
( ) 3 30,17 10 50 8,5 10L R r H = + = =
5-( )22 3 4
0
10, 5 8, 5 10 0,18 1, 38 10
2bE LI J
= = =
----------------------------------------------------------------------------------------------------------------))3,5
1-3 2 3 3CH COOH H O CH COO H O + + = +
:-2
3-(3
0 0
q q
f
m
H Ox
x C V
+ = =
)[ ]
2
3 3 3
3 0 3
q q q
rq
q q
CH COO H O H OQ
CH COOH C H O
+ +
+
= =
)
( )3 3 3 3
3 3 3q H O CH COO H O CH COOq q qH O CH COO H O + +
+ + = + = +
4-(( ) ( )
3 3
3 40
3 30
0,016 0,41 / 4,1 10 /38,6 10q
H O CH COO
H O mol m mol L
+
+
= = = = +
3 2 3 3 OCH COOH H CH COO H O + + = +
00
0 0C V
----0 0C V x
qq-----0 0 qC V x
mxmx-----0 0 mC V x
0,2
40
( )t ms
( )i mA
0,17
113,4
180
7/25/2019 Bac2011_M2
2/5
2
( ) ( )
3 3
3 41
3 31
0,0360,93 / 9,3 10 /
38,6 10q
H O CH COO
H O mol m mol L
+
+
= = = = +
( )( )
430
0 2
0
4,1 100,041 4,1%
10
f
m
H Ox
x C
+
= = = = =( )
( ) 43
1 2
1 2
1
9,3 101,86 10 1,86%
5 10
f
m
H Ox
x C
+
= = = = =
( )( )
( )
( )
2 24
3 0 5
0 2 4
0 30
4,1 10 1,75 1010 4,1 10
q
q
q
H OQ
C H O
+
+
= = =
( )( )
( )
( )2 2
43
1 5
1 2 4
1 31
9,3 101,76 10
5 10 9,3 10
q
q
q
H OQ
C H O
+
+
= = =
-)
-
.
--------------------------------------------------------------------------------------------------------------)3,5(
-1 ) .(:-2
236 94 140 x= + +2x=92 38 Z= +54Z=
:235 1 94 140 1
92 0 38 54 0 2U n Sr Xe n+ + +
-3 .
4-(234,99332 93,89446 139,89194 1,00866 0,198i fm m um = = =
(( )2
27 8 112 0,198 1, 66 10 3 10 2,96 10libE m c J = = =
:
:931,5 184,44libE m MeV= (= 13
1 1,6 10eV J= (
( )/C mo L( )1.q S m ( )3 /qH O mol L+ %rqQ
0S2
1,0 100,01644,1 104,151,75 10
1S25,0 100,03649,3 101,86
51,76 10
n
n
n
n
n
n
n
7/25/2019 Bac2011_M2
3/5
3
(
235
:23 212,5
6, 02 10 6, 4 10235
A
mN N
M= = =
2,5 :21 21 11 11
' 6,4 10 6,4 10 2,96 10 1,89 10lib libE E J= = =
-:) .
) .)-
1mol-54
CH 16g). (
16
5
8 10 J
m111,89 10 J63, 78 10 3, 78m g t= =
---------------------------------------------------------------------------------------------------------------------))3
)-1 .
)2
/ 2
L TT L L
M M vF G M
rr= =
14
6
81,3 4 101020 /
384 10
T LGM G M v m sr r
= = = =
:6
2 6,28 384 101094 /
25,5 24 3600
rv m s
T
= = =
: .25,5Jour27,3jour
)-2 1r2r3r 1T2T3T
22 2 2
31 2
3 3 3
1 2 3
4....
S
TT Tk
GMr r r
= = = = .= .
.:
)( )
2 2
3
4
LL A
T
GMR h
=
+
( ) ( )3
6 33
11 22
1,74 10 110 102 6,28 7142,3 2
6, 67 10 7, 34 10
L A
A
L
R hT s h
GM
+ += = =
( )-3 ( )
( )
223 3 6 22 3
2 2
24384 10 8,7 10
25,5 24S
L
Tr r m
T= = =
22 73 8, 7 10 4, 43 10 44300Sr m km= = =
-4 .
.
.
)3,5
(-------------------------------------------------------------------------------------------------------------
=0t)-1 .( )v t))2
.( )t))1
( )x t1t) .=2,25t s
(=2,25t s
( )v t .)
2-
25
2,22 /2,25a m s= =
( )m ( )/v m s
( )t s ( )t s 0,5 0,5
1 1
2,252,25
5
5,6
7/25/2019 Bac2011_M2
4/5
4
)(:
:)-3
) :
f P R ma+ + =r r r
r
:
f ma =
( )20 2, 22 44, 4f N= =
:2,22)-4dv
dt= .
.=5C+ =2,22v t C=5 /v m s=0t
2, 22 5dx
tdt
21,11+ = 5 'x t t C= + ' 0C+ =
21,11 5t t= +
::
2
0 0
1
2x a t v t x= + +
0 5 /v m s=0 0x = 2
1,11 5x t t= +
:) 5 2,25
5,622
d m
= =
:
)5,6d m=. (
----------------------------------------------------------------------------------------------------------------))3
1-(27%
100g
( )S
27
NaOH
.
NaOH
eau
d
= 1,3 1 1,3 /NaOH g mL = =
:NaOH100g100
76,921,3NaOH
mV mL
= = =.
27
NaOH:27
0,67540
n mol = =
0
0,6758,8 /
76,92
nC mol L
V= =
: :02710 10 1,3 8,8 /40
PC d mol L= =
)8,8 10
8800,1
B BA
A
C VV mL
C
= = =
) .880mL50mL
880
17,650
= )17(
.
-2 500
1050
V mL= =
:
5mL
( )S
500mL
.))495mL
1 1,5 20,5
( )2/a m s
( )t s
2,22
Rr
Pr
fr
7/25/2019 Bac2011_M2
5/5
5
.pH:-3
(
.
):) ) ( ) ( )3 2, , , 2Na OH H O Cl Na Cl H O+ + + + = +
)
E( )17,6 ; 7
:( )S):
0,1 17,60,176 /
10
A AEB
B
C VC mol L
V
= = =
:
0 50 50 0,176 8,8 /BC C mol L= = =
7
17,6( )AV mL
pH
E