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8/8/2019 dipole RC ter PC SM cours 1
1/8
Allal mahdade http://sciencephysique.ifrance.com Page 1
RCDipole RC
I Condensateur .
1
1: .
.
.:
1
UAB UAB=E.
2 2 . qAqB AB
. B A
A qAB qB
3 qAqB
qA=- qB qA+qB=0 :qAqB :qA=- qB.:
. Q
(C)Q=+qA=-qB. 2
A: i>0
i
8/8/2019 dipole RC ter PC SM cours 1
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Allal mahdade http://sciencephysique.ifrance.com Page 2
(V)u2 4 6 8 10
q (mC)
5
10
15
20
25
i(t) A:
qA(C)t(s)i(t)(A).: :
(I=Cte)
:Aq I. t=
3 :. 2
. I=100A
.
. .
10 :
1086420uAB(V)21,417,112,98,64,30t(s)
0,02140,01710,01290,00860,00430qA(C):
1 qA t .qA=I.t qA.
2 qA=f(uAB) .3 .
O :
qA=K.uABK :K=2,14mF
C
:qA=C.uAB
C :F
: mF=10-3FF=10-6FnF=10-9F
8/8/2019 dipole RC ter PC SM cours 1
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Allal mahdade http://sciencephysique.ifrance.com Page 3
II . 1
A B 1 2
1 AB 2 AB
AB
1 2
q q q i i i
q C U C Uq C.U
C C C
= + = +
= +=
= +
:n
ii 1
C C=
=
. : .
2 A
BAB AD DB
1 2AB
1 2
1 2
U U U
Q QQU
C C C
1 1 1C C C
= +
= = +
= +
:n
i 1 i
1 1C C=
=
: .III RC .
1 RC R C.
u(t) : :
t0:u(t)=0 t>0:u(t)=E1 :
2t>0:u(t)=-E t0:u(t)=0
2 :
8/8/2019 dipole RC ter PC SM cours 1
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Allal mahdade http://sciencephysique.ifrance.com Page 4
3.Y1Y2 . 1. 2.
.:
I 1
1 Y1 .
Y1 uDB=E
: 2 Y2
Y2 uC
. t=0 4
2 1 :
CC
duRC u E
dt+ = uC(t) t
RC . :
uR+uC=u u=E.
uR(t)=Ri(t) :dqi(t)dt
=(Cq(t C.u (t)=
Cdu (t)i(t) Cdt
= :
CC C
duRi(t) u (t) E RC u E
dt+ = + =
22 :
xtCu (t) Ae B= + ABx .
xB. :
xt xtCC
duRC u E RC.( Axe ) Ae B E
dt1 1
RC.x 1 xRC
E B 0 B E
+ = + + =
= = =
= =
:
t
Cu (t) Ae E
= +
8/8/2019 dipole RC ter PC SM cours 1
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Allal mahdade http://sciencephysique.ifrance.com Page 5
uC(0)=0 A. uC(t) t. uC(0)=0 t t=0.uC(t=0+)=uC(t=0-)=0
C
t
C
u (0) A E 0 A E
u (t) E(1 e )
= + = =
=
3 )4(
: .t
Cu (t) E(1 e )
= 3 1 :
: uC(t)
: . .3 2uC(0)uC()uC(t) t4 RC
.= R.C 4 1
. =RC
:
I tdu
i C Cdt V
= =
:
Uu Ri R
i = =
I t U
R.C . tU i
= =
.s : RC .
4 2 R.C.
.=33s RC=33s5 uC(t).5 1 uC(t=)E.
1Cu ( ) E(1 e ) 0,63E
= =
5 2 ..0,63E
5 3 Cdudt
t=0E
.
8/8/2019 dipole RC ter PC SM cours 1
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Allal mahdade http://sciencephysique.ifrance.com Page 6
c
t 0
dudt
=
uC(t) t=0ct 0
du Et
dt=
=
uC(t) t=ouC=E t=.6 .
RC :
RC
Cdudqi C.dt dt
: = =t
Cu (t) E(1 e )
= RC =:
t tCdudq 1 Ei C. CE(0 e e
dt dt RC R
= = = =
II 21 Y1
. :Ru Ri=
2 Y2 Y2 uC
2(t=0) 5
(uC(0)=E).
2 1 :C
C
duu 0
dt + =
uC(t) t RC RC.
:
R C C
C
CC
u u 0 Ri u 0
dudqi i C
dt dt
duRC u 0dt
+ = + =
= =
+ =
22
:xtCu (t) Ae BxB A+ =
. xB.
:
tEi(t) e
R
=
8/8/2019 dipole RC ter PC SM cours 1
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Allal mahdade http://sciencephysique.ifrance.com Page 7
xt xtCC
duRC u 0 RC.( Axe ) Ae B 0
dt1 1
RC.x 1 xRC
B 0
+ = + + =
= = =
=
:t
Cu (t) Ae
= uC(0)=E A. uC(t) t.
uC(0)=0 t t=0.uC(t=0+)=uC(t=0-)=E
C
t
C
u (0) A E A E
u (t) Ee
= = =
=
:t
Cu (t) k e
= k.
3 .
:uC(0)-uC()uC(t) t
.uC(0)=E t uC
k.k=E
4 5 .
t=0 .0,37E
6 uC(t) t=5
C
C
u (5 )
u (0)
.
3C
C
u (5 )6,73.10 0,67%
u (0) = =
t=5 .
7 1
8/8/2019 dipole RC ter PC SM cours 1
8/8
Allal mahdade http://sciencephysique.ifrance.com Page 8
8
:tE
i(t) eR
=
Cdudqi C.
dt dt: = =
t
Cu (t) Ee
=
RC =:t
Cdudq Ei C. edt dt R
= = =
:tE
i(t) eR
=
IV .1
: .
:2 K
.
.
.
2 .
:P Cu .i= Cdudqi C
dt dt: = =
P2c
C C
du d 1C.u Cu
dt dt 2
= =
P2e
e C
d 1Cu K
dt 2
= = +(e(0 0 = Cu (0) K=0=0
:
2e C
1Cu
2 =
RAM
.