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8/18/2019 Conso Carb
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c (k)
{ki, vi}
ki
vi
vi =
ˆ ki
ki−1
c (k) dk
ri
{ki, vi, ri}
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i
ri−1 +´ ki
ki−1c (k) dk
ri
vi = ri−1 − ri +
ˆ ki
ki−1
c (k) dk
c
ci = vi
ki − ki−1
=
´ ki
ki−1c (k) dk
ki − ki−1−
ri − ri−1ki − ki−1
ri
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c)
•
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•
r
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α = 0, 5
•
mi = µi = 0 i = 0, 1, . . .
i = 1, 2, . . .
• m
mi = mi−1 + vi
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• µ
µi = max
mi , µi−1 + (mi+1 − µi−1) ·
ki − ki−1ki+1 − ki−1
•
c
ci = 100 · µi − µi−1ki − ki−1
i = n
ki+1 = 0 mi+1 = 0
µn = max
mn , µn−1 ·
kn
kn−1
cn = max
mn − µn−1kn − kn−1
, µn−1
kn−1
k0 ≈ 0 v0 ≈ 0
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