1

Variantim 78 וריאנטים

August 2019

מקוריות: פתרונים והערות

Originals: Solutions & Comments

IRT judges: #2: Valery Kopyl (2019) #3: Jiří Jelínek (2018-9) #n: Gerhard E. Schoen (2018-20)

Studies: Steffen Slumstrup Nielsen (2019) H#2-3: Ricardo Vieira; H#>3:Aleksandr Semenenko (2019);

S#: Genady Kozyura (2019-20) Fairies: Hans Gruber (2019)

Editors: :עורכים Orthodox: Ofer Comay

Studies: Gady Costeff (Please send originals in pgn format)

Fairies: Michael Grushko

ofercomay@gmail.com

costeff@gmail.com

bargrushko@bezeqint.net

עופר קומאיבעיות רגילות:

גדי קוסטףסיומים: (pgn)נא לשלוח מקוריות בפורמט

מיכאל גרושקובעיות אגדתיות:

3243

Miguel Uris

Spain

#2*vv 11+8

1... cxd5 [a] , Rxd5 [b] , Bxd5 [c] 2. Se8 [A] #

1... c5 2. Rb6 [B] # 1... f5 2. Be5 [C] # 1... Bb1 2. Sc4 [D] #

1. Rc4? [2. Rxc6#] 1... Qc2! 1. Re5? [2. Se8#] 1... Bb6!

1. Rd4! [2. Se8 [A] #] 1... cxd5 [a] 2. Rb6 [B] # 1... Rxd5 [b] 2. Be5 [C] # 1... Bxd5 [c] 2.

Sc4 [D] # 1... Sf6 2. Bf8# 1... Bxd4 2. Qe7# 1... Re5 2. Bxe5#

Luukkonen - Changed & Transferred mates (author)

Three mate transfers and two pin-mates in the solution (PE)

3244

Miroslav Svitek

Slovakia

#2v 9+11

1.Sbc3? ~ 2.Sd5# 1...axb2 C 2.a3# 1...Bxb6 C 2.Qxb6# 1...Qc5 A 2.Qxc5# 1...Qd6 A

2.Qxd6# but 1...Se3!

1.Sbd2! [2.Qxc4#] 1...Sxb2 AB 2.Qc3# 1...axb2 BC 2.a3# 1...Bxb6 CD 2.Qxb6# 1...Qc5

DA 2.Qxc5# (1...Se3 2.Qc3#)

cyclic change of four defensive motives AB-BC-CD-DA A - direct guard of the threat

square B - indirect guarding by unpinning C - creating flight by unblocking of the royal

square D - pinning of the threat unit (author)

While there is only one threat, each thematic defense has two defensive motives – these

show cyclicality in the four thematic defenses. From my point of view, such work is better

shown with two different threats with each defensive motive defending one of them (PE)

3245

Miroslav Svitek

Slovakia

#2 11+10

1.Bc2! [2.Sd3#] 1...Se1+ AB 2.Rxe1# 1...Bxc4 BC 2.Sd7# 1...Qxf7+CA 2.Sxf7#

1...exd5 CD 2.Rxd5# 1...dxc5 DE 2.Bc7# 1...Qf6+ AF 2.Bxf6# /1...Sf4 2.gxf4#/ cycle

defensive motifs AB-BC-CA spiral defensive motifs AB-BC-CD-DE radical change

defensive motifs BC-DE-AF A - checking B - direct guard of the threat square C - creating

flight by capture D - creating flight by unblocking of the royal square E - capturing of the

threat unit F - creating flight by line interference (author)

'$'I'd'd d'H'dpGn 'dpi'd'd dPdPd'4' ')'dR)'d d'd'g'd' bH'd'd'1 d'd'!'d'

'd'd'1'd d'd'dpd' ')Bd'd'd g'd'd'd' pip!Nd'd 0bdpd'd' P$'d'dpd $Ndnd'I'

'd'G'drH d'd'dR1' 'd'0pdpd dbHPi'd' 'dPd'd'0 d')BdK)' pd'd'dnd d'dRd'd'

2

3246

Gerhard Maleika

Germany

#2v 12+7

1.Qg8? (2.Qb3 Qe6 Qg3) 1...Qxg1 2.Qb3 Qe6 Qg3 1...Qxh2 2.Qb3 Qe6 1...cxb5 2.Qb3

Qg3 1...Bd2 2.Qe6 Qg3 1...Qxg2 2.Qb3 1...Bxe2 2.Qe6 1...Bxb2 2.Qg3 1...c4!

1.Qh8! (2.Qc3 Qe5 Qh3) 1...Qxg1 2.Qc3 Qe5 Qh3 1...Qxh2 2.Qc3 Qe5 1...cxb5 2.Qc3

Qh3 1...Bd2 2.Qe5 Qh3 1...Qxg2 2.Qc3 1...Bxe2 2.Qe5 1...Bxb2 2.Qh3 1...c4 2.Qd4

Combinative Separation of 3 mates in 2 phases (author)

A nice scheme to achieve full separation of the three mates in all combinations. The defense

defending all three threats is the refutation of the try and is met with a new mate in the

solution (PE)

3247

Gerhard Maleika

Germany

#2 11+6

1.Qxg7! (2.Qe5 Sf6 Sf4)

1.-Bxd3 2.Qe5 Sf6 1.-Bxh7 2.Qe5 Sf4 1.-Qxf7 2.Qe5 Qd4 1.-Qf2 2.Qe5 Rd7

1.-Rxe8 2.Sf6 Sf4 1.-Qc7 2.Sf6 Qd4 1.-Qe3 2.Sf6 Rd7 1.-Qe7 2.Sf4 Qd4

1.-Qa1 2.Sf4 Rd7 1.-Qd4 2.Qxd4 Rd7

Combinations of double-mates of 5 different mates (author)

3248

Givi Mosiashvili

Georgia

#2*v 8+9

1...Be4 2.Be3#, 1...Sd5 2.Sb5# ,1...Qh6/d7 2.Qe5#

1.Ree5? [2.Be3#] 1...Qh6 2.Sb5#, #, 1...Sd5 2.Rad5#,1...Qe5 2.Qe5#, but 1...Rh3!

1.Rae5! [2.Sb5#] 1...Qd7 2.Be3#, 1...Be4 2.Ree4#, 1...Qe5 2.Qe5#, 1...c3+ 2.dc3#

The full form of the Sushkov theme, pseudo Le Grand theme, a simple change of mats 2x2

and 3x1 (author)

The Sushkov theme involves the prevention of potential threats. After 1.Raxe5? both d5 and

e4 are guarded, but 2.Be3 is not a threat as e5 will be unguarded. Same in the solution with

2.Sb5 (PE)

3249

Yoel Aloni

Netanya

#2v 8+5

1.Qa3 ? [2.Bg2#] 1...Kd5 2.Qxa8,Qf3# but 1...Bb3 !

1.Qb4 ? [2.Sd6#] 1...Kd5 2.Bg2# but 1...Bc4 !

1.Kd2 ! [2.Bg2#]

1...Kf3 2.Sd6# 1...Kd5 2.Qxa8#

Nice try play with a Dombrovskis paradox (on Bg2#) and return of the Sd6# threat as mate.

I would add a black pawn on a7 to have the unique 1...Kd5 2.Qf3# in the first try, and full

1x3 change (PE)

3250

Pavel Murashev

Russia

#2*vv 8+13

1...Qc3 2.Rxb6/f1# (AB)

1...Qd4 a 2.Rxb6 A# (2.Rf1+? Qf4!) 1...Qxe5 b 2.Rf1 B# - self-pin (2.Rxb6 +? Ke6!)

*1...Bg6 c 2.Qd8 C#

1.Be4! [2.Qd8 C#]

1...Qd4 a 2.Rf1 B# (2.Rxb6+? Qd6!) 1...Qxe5 b 2.Rxb6 A# - self-pin (2.Rf1+? Kf5!)

(1...Bf8 2.Qxg5#, 1...Bg7+ 2.Qxg7#)

1.S8:b6? [2.Sd7#] 1...Qxe5! (b) 1...Qxb6 2.Rxb6/f1# (AB)

1.Sxe3? [2.Rf5#] 1...Kxe5! 1...Qxe5 (b) 2.Rxb6/f1# (AB) 1...Bg6 (c) 2.Sxg4#

Dombrovskis, Mekihovi, Reciprocal mate changes (new mechanism) + duel bQ and wR +

self-pin in 2 phases! (1...Qxe5), dual avoidance. No of white pawns + 8 of black pawns!

(author)

A very nice mechanism of reciprocal changes plus some trendy additions (PE)

3251

'd'!'d'd d'dPI'd' 'dpd'd'd dB0'd'd' Rd'd')'d d'd'i'd' ')pdNdP) d'gbG'Hq

'4'dBd'! 1'd'dR0N 'dRd'dbd dPdkd'd' '0'd'dPd d'dPd'GK 'd'dNd'd d'd'd'd'

'd'd'd'! d'd'd'1r 'h'd'dbd $'d'0'G' p)pi'd'd H'dpd'd' 'I')'d'd d'd'$'d'

nd'd'!bd d'd'd'd' '0'd'$'d d'd'dN$p 'd'Gkd'd d'd'd')' 'd'd'd'd d'I'dBd'

'dNd'dQI d'd'dpd' p0'd'i'g d'0B$'0b 'dNd'dpd 4'dp0'd' '1'd'd'd GRd'd'd'

3

Luke Neyndorff

USA

#2 8+11

1...e4 2.Qd6#

1.Qxg6!

1...b4 2.Bc4# 1...c4 2.Sb4# 1...e4 2.Qxf5# 1...f4 2.Qe4# 1...Sc~ 2.Qxe6# 1...Se~ 2.Qd6#

A classical “block” problem. The mate change (and transfer) are a good point. A simple

transfer of WPe2 to f3 enable the removal of BPg6

3252

Yitzhak Nevo

Ein Harod

#3 5+3

1.Qc6 ! [2.Qd7 ~ 3.Re3# 2...Bxd5 + 3.Qxd5# 2...Be6 3.Qxe6#]

1...Kf5 2.Qf6 + Ke4 3.Re3# 2...Kg4 3.Qf3#

1...g4 2.Re3 + Kf5 3.Qf6#

1...Ke5 2.Qf6 + Ke4 3.Re3#

Pleasant classical style problem (PE)

3253

Yitzhak Nevo

Ein Harod

#3 10+7

1.Bc5 ! zz

1...h2 2.Sd3 zz 2...Rg4 3.Bxf3# 2...Bg4 3.Rf4# 2...Rh3/Rf4/Bg6 3.Rf4/Rxf4/Bxf3#

1...Bg4 2.Rf4 + Kxe5 3.Sd3#

1...Rg4 2.Bxf3 + Kxe5 + 3.Bd4#

and 1...Kxe5 + 2.Bd4 + Ke4 3.Re5# 1...Rf4 2.Rxf4 + Kxe5 3.Sd3#

1...Bg6 2.Bxf3 + Kxe5 + 3.Bd4#

Good key and interesting Grimshaw play in the 2nd black move after 1...h2 and in the 1st

black move. The cross-check variation, forcing a different white mate, is especially nice

(PE)

3254

Amatzia Avni

Givat Shmuel

Ded. to Netanya

Chess Festival

Draw 6+5

1.Bg5+! (1.Nd5+ Kf5 2.Ne3+ Nxe3 3.Bxe3 g1=Q 4.h4 Qg4 5.Bg5 Qxg5! 6.hxg5 h4

7.Kf7 h3 8.Nxg6 Kxg5! 9.Ne5 Kf4! -+) 1...Kxg5 (1...Ke5 2.Nexg6+ Kd6 3.h3 g1=Q

4.hxg4 =) 2.Nh7+ Kh6 (2...Kf4 3.Nxg6+ Ke4 4.Ng5+ =) (2...Kh4 3.Nxg6+ =) 3.h4!!

g1=Q 4.Ng5 (4.Kh8 Qa1+) 4...Nf6+ (4...Ne5 5.Kh8) (4...Qxf2 5.Nf7+ Qxf7+ 6.Kxf7 =)

5.Kh8 Qxg5 6.f4!! (6.hxg5+ Kxg5 7.f4+ Kg4 8.Nxg6 Nd5 -+) 6...Qd5 the same rejoinder

will come after other queen moves. 7.Nf5+ and stalemate.

'd'd'd'd 0'h'G'H' Bdpdndpd dp0k0pd' 'd'0'd'd d'dPd'!' 'dNIPd'd d'd'd'd'

Qd'd'd'd d'd'dbd' 'd'd'd'd d'dNd'0' 'dKdkd'd d'd'd'dR 'd'd'dNd d'd'd'd'

'd'd'd'd d'H'dpd' 'Gpd'$'d $'d')'db Kd'dkd'4 d'd')pdp 'dPd'd'd d'H'd'dB

'd'd'HKd d'd'H'd' 'd'd'ipG d'd'd'dp 'd'd'dnd d'd'd'd' 'd'd')p) d'd'd'd'

4

3255

Bogusz Piliczewski

Poland

Win 5+6

1.Bb5+ Kd8 2.c4 Nh4 2...Nf4 3.c5 Ng6+ 3.c5 Ng6+ 3...Nf3+ 4.Kd5 Nd4 5.Bf1+- or

3...g2 4.c6 Ng6+ 5.Kf6 4.Kf6! 4.Ke6 Nf4+ 5.Ke5 Ng6+ 4...g2 4...Nf4 5.c6 Nd5+ 6.Ke5

Nc7 7.Bf1+- 5.c6 g1=Q 6.c7+ Kc8 7.Ba6+ Kd7 8.c8=Q+ Kxd6 9.Qb8+ Kd5 9...Kc6

10.Bb5+ Kc5 11.Qxa7+ +- 10.Bb7+ Kc5 11.Qxa7+ 1-0

3256

Yechiel Robinson

USA

Win 3+2

1.a4 Kg2 (1...Ne5 2.Kg5! Nf3+ 3.Kf6 Nxe1 4.a5 Nd3 5.a6 Nb4 6.a7 Nd5+ 7.Kf7! Nb6

8.Ke8 Kg4 9.Kd8 Kf5 10.Kc7 and wins.) (1...Nd8 2.Kg5 Kg2 3.Kf4 transposes to the

main line.) 2.Kg4 Nd8 (2...Ne5+ 3.Kf5 Nc4 4.Ke4 Kf1 5.Bb4 Ke2 6.Kd4 Nb6 7.a5)

(2...Kf1 3.Bg3 Nd8 (3...Ke2 4.Bc7 traps the knight.) 4.Kf3 Nb7 5.Ke3 transposes to the

main line after 10.Ke3.) 3.Kf4! (3.a5? Nc6 4.a6 Kf1 5.Ba5 Ke2 6.Kf5 Kd3 7.Ke6 Kc4

8.Kd6 Kb5 =) 3...Kf1 4.Bh4 (4.Bb4? Ke2 5.Ke4 Nb7 6.Kd5 Kd3 7.Kc6 Kc4 =) 4...Nb7

5.Ke3 Na5 6.Be7 Kg2 (6...Nb3 7.Kd3!) 7.Kd3 Kf2 (7...Kg3 8.Bb4! (8.Bd8? Nc6

9.Bc7+ Kf3 10.Kc4 Ke4 11.Kc5 Nd4 12.Kb6 Nb3 =) 8...Kf4 9.Bxa5 Ke5 10.Kc4 Kd6

11.Kb5 Kd7 12.Kb6 Kc8 13.Ka7) (7...Nc6 8.Bf6 Kf3 9.Kc4 Ke4 10.Bc3 Kf5 11.Kc5)

8.Bh4+! (8.Bd8 Nb7 9.Bb6+ Ke1! =) 8...Kf1 (8...Kf3 9.Bd8 Nb7 (9...Nc6 10.Bc7 Kg4

11.Kc4) (9...Nb3 10.Kc3 Ke4 11.Kxb3 Kd5 12.a5 Kc6 13.a6 zugzwang.) 10.Bb6 Kf4

11.Kd4 Kf5 12.Kd5) 9.Bg3 Nb7 10.Ke3 Na5 11.Kd4 Ke2 12.Bc7 Nb7 13.Kd5 Kd3

14.Kc6 Kc4 15.Kxb7 Kb4 16.a5 1-0

3257

Daniele Gatti

Italy

Win 9+9

1.Nf8! (1.Kg8 Rxg2 2.Kf8 Rxg6 3.Nxb5 (3.Re1 Rd8+ 4.Ke7 Rdg8 5.Nc2 Kb8 6.Rxb5

(6.Rb3 R6g7+ 7.Kxd6 Rd8+ 8.Kc5 Rc8+ 9.Kxb5 Rxc2)) 3...Rh6 4.Rxa2+ Kb8) (1.Ne5

dxe5 2.dxe5 Rxg2 3.Nxb5 Rd8+ 4.Kh7 Rd7+ 5.Kh6 Rd8 6.Rxa2+ Kb8 7.Kh7 Rd7+

8.Kh8 Rd8+) 1...Rxg2 2.Ra4+!! (Thematic try: 2.Nxd7? Rg8+ 3.Kh7 Rg7+ 4.Kh6 Rg6+

5.Kh5 Rg5+ 6.Kh4 Rg4+ 7.Kh3 Rg3+ 8.Kh2 Rg2+ 9.Kh1 Rh2+ 10.Kg1 Rg2+ 11.Kf1

Rf2+ 12.Ke1 Re2+ 13.Kd1 Rd2+ 14.Kc1 Rd1+ 15.Kc2 Rd2+ 16.Kc3 (16.Kb3 Rxb2+

17.Kc3 Rc2+ 18.Kd3 Rc3+ 19.Ke2 Re3+ 20.Kf2 Rf3+ 21.Kg2 Rg3+ 22.Kh1 Rh3+

23.Kg1 Rg3+ 24.Kf1 Rf3+ 25.Ke1 Re3+ 26.Kd1 Rd3+ 27.Kc1 Rc3+ 28.Kb2 Rc2+

29.Kb3 Rb2+ 30.Kc3 Rc2+ 31.Nxc2 Stalemate) 16...Rd3+ 17.Kxd3 Stalemate) (2.Ne6 Re7

3.Nc7+ Kb8 4.Rb3 Re4 5.Rh3 Rf4 6.Ne6 Rf6 7.Re1 a1=Q 8.Rxa1 Rxe6 9.Rf1 Re8+

10.Kh7 Re7+ 11.Kh6 Re6+ 12.Kh5 Re8) 2...bxa4 3.Nxd7 Rg8+ 4.Kh7 Rg7+ 5.Kh6

Rg6+ 6.Kh5 Rg5+ 7.Kh4 Rg4+ 8.Kh3 Rg3+ 9.Kh2 Rg2+ 10.Kh1 Rh2+ 11.Kg1

Rg2+ 12.Kf1 Rf2+ 13.Ke1 Re2+ 14.Kd1 Rd2+ 15.Kc1 Rd1+ 16.Kc2 Rd2+ 17.Kc3

Rd3+ 18.Kb4 Rb3+ 19.Ka5 (19.Kxa4 Rb4+ 20.Ka5 Rb5+ 21.Nxb5 Stalemate)

19...Rb5+ 20.Nxb5 wins.

3258

Vladimir Samilo

Ukraine

Draw 8+7

1.Bf4 1.Rd6? Qxd6 2.Bxd6 Bxg1 3.Kxg1 f6 4.Kf2 Kf7 5.Ke3 Ke6 6.Bf4 Kd5 -+

1...Qa6! 1...e3 2.Bxh6 exd2 3.Bxd2 Bxg1 4.Kxg1= 2.Be3 2.Qe1? e3 3.Re2 Qc6+ 4.Kg1

Qe4 5.h4 Bd4 6.h3 Ra8 7.Bxe3 Ra1-+ 2...Bxe3 3.Qxe3 Qf1+ 4.Qg1 e3 4...Qxh3

5.Qd1= 5.Qxf1 exd2 6.Kg2! Re1 7.Qa6!! 7.Qc4 Rc1 8.Qa4 d1=Q 9.Qe8+ Kh7 10.Qe4+

g6 -+ 7...d1=Q 8.Qc8+ Kh7 9.Qf5+ Kg8 9...g6 10.Qxf7+ 10.Qc8+ positional draw.

'd'd'd'd 0'dkd'dp 'd')'d'd 0'd'I'd' 'd'd'd'd dPdBd'0' 'dPd'dnd d'd'd'd'

'd'd'd'd d'd'dnd' 'd'd'd'd d'd'd'dK 'd'd'd'd d'd'd'dk Pd'd'd'd d'd'G'd'

kd'd'd'I dpdrd'd' ')'0'dNd dpdpd'd' '$')'d'd H'd'd'd' p)'drdPd $'d'd'd'

'd'drdkd g'G'dp0' 'd'd'd'1 d'd'd'd' 'd'dpdPd d'd'd')P 'd'$'d') d'd'd'!K

5

3259

Michal Hlinka

Mario Garcia

Slovakia/Argentina

Win 9+6

1.c6! (1.Bb2? exd5! 2.h6 Nxd4! (2...Bh4? 3.Kg7 Nxd2 4.c6 Ne4 5.c7 Bf6+ 6.Kf8 Nd6

7.h7 N8b7 8.Bc1 Kxa7 9.Bh6 +-) 3.c6 N8xc6 4.h7 Bg3! 5.f6 Be5 6.Kg7 Ne6+ 7.Kxf7

Ng5+! =) 1...Bxd4+ (1...Nxc6 2.dxc6 +- similar to solution) 2.f6! (2.Kg8? Nxc6 3.dxc6

Kxa7 4.f6 Nxc1! (4...Bxf6? 5.Kxf7 +- similar to solution) 5.Kxf7 Nd3 6.h6 Kb6 (ab) 7.h7

Ne5+ (ba) 8.Kxe6 Ng6 =) 2...Nxc6 (2...Bb6 3.Bb2! exd5 4.Kg8! Ne6 5.Kxf7 Ng5+ 6.Kg6

+-) (2...Be5 3.Bb2 Bxb2 4.c7 +-) 3.dxc6 Bxf6+ 4.Kg8 Kxa7 5.Kxf7 Bg5 (5...Bh8

6.Ba3! Kb6 7.Be7! Nxd2 8.Bf6! +-) (5...Bd4 6.Kxe6! Kb6 7.Kd6 Na5 8.c7 Nb7+ 9.Kd5!

+-) 6.Ke8! (6.Kxe6? Nc5+! 7.Kf5 Bh6 8.Ba3 Nd3 (8...Nb3? 9.Be7 Bxd2 10.Bg5 Bc3

11.Ke6 Kb6 12.Kd5 Bg7 13.Kd6 Bf8+ 14.Be7 +-) 9.Be7 Kb6 10.Bg5 Bg7 =) 6...Kb6

7.d4! Bxc1 (7...Bf6 8.Kd7 Bxd4 9.Ba3! +-) (7...Nxc1 8.Kd7 +-) (7...Kxc6 8.Bxg5 Nxd4

9.h6 +-) 8.Kd7 Bf4 9.h6 Bxh6 (9...Nxd4 10.h7 Nb3 11.Kxe6! (11.h8=Q? Nc5+ 12.Ke7

Kxc6 =) (11.c7? Nc5+ 12.Ke7 Kxc7 =) 11...Kxc6 12.h8=Q +-) 10.c7 Nxd4 11.c8=Q wins.

3260

Michael Pasman

Yochanan Afek

Meitar/Amsterdam

Draw 6+5

1.O-O+! (1.Kf2 Ra3 2.Ra1 g4 -+) (1.Kd2 Ra3 2.Ra1 Rxg3 -+) 1...Ke7 2.Ra1 Ra3 3.g4!

Kd7 4.Kh2! Kc6 5.g3! Ra8 6.Kg2 (also 6.Kh3) 6...Kb5 7.c6 Kc4 8.c7 Kb3 9.Re1!

Rc8 10.Re3+ Kb4 11.Re4+ Kb5 12.Re1 Rxc7 13.Ra1 Ra7 14.Kh3 Kc4 15.Rxa2!

Rxa2 Stalemate.

3261

Daniel Porat

Roy Erlich

Ashkelon/R. Hasharon

Draw 5+5

1.Rf2 1.Re2 Qd8+ 2.Kf4 Qxh4 3.Re8+ Kf7 1...g2 1...Qe5+ 2.Rf5 Qe7+ (2...gxf5 3.gxf5

Qe7+ 4.f6) 3.Rf6 Qe3+ 4.Rf4 g2 5.Qh2 $10) (1...Qb5+ 2.Rf5) (1...gxf2 2.Qxf2) (1...Qd8+

2.Rf6 Qa5+ 3.Rf5 Qd2+ 4.Rf4 2.Rf8+! Qxf8 3.Qf2 Qe7+ 4.Kf4 Qf6+ 5.Kg3 Qxf2+

6.Kxf2 Kf7 7.Kxg2 Ke6 7...g5 8.Kf3 Kf6 9.Ke4 Kg6 10.Ke5 8.Kf2 g5 9.Ke2 Kd5

10.Kd3 Ke5 11.Ke3 draw.

3262

Menachem Witztum

Emanuel Navon

Tel Aviv/Holon

H#2 b)Bg2d5 10+11

c)Bg2a2

a) 1.Bb5 Sb3+ (Sb5,Sf3?) 2.Kxc6 Bxe4#

b) 1.Kb4 Sf3 (Sb3,Sb5?) 2.Ka3 Bc5#

c) 1.Kd6 Sb5+ (Sb3,Sf3?) 2.Ke5 Rd5#

The white knight must be removed to enable the solutions, but only 1 of 3 possible squares

can be played in each of the solutions (PE)

Daniel Papack sent the following version that should not participate in the IRT:

H#2 b)Bg8e4 10+11

c)Bg8b1

kd'h'd'I )'d'dpd' 'd'dpd'd d')PdPdP 'd')'d'd dnd'd'd' 'd')'g'd d'G'd'd'

'd'd'd'd d'd'dkd' 'd'dpd'd d')')'0' 'd'd'd'd d'4'd')' pd'd'dPd d'd'I'dR

'1'd'dkd d'd'd'dp 'd'd'dp) d'd'd'I' 'd'd'dP! d'd'd'0' 'd'd'd'$ d'd'd'd'

'd'd'd'd d'0'0'd' 'dPdP0'd d'i'dP0' bd'Hpd'd d'gRG'd' 'hPdPdBI d'1nd'd'

'd'dKdBd d'd'd'd' 'd'd'd'd 0Pi')Pd' 'd'H'd'd dPh'hPd' p0'dPd'd d'dQd'd'

a) 1.Kb4 Sc6 + 2.Ka3 Qd6#

b) 1.Kb6 Sc2 2.Kc7 Qd8#

c) 1.Kd5 Se6 + 2.Kxe5 Qd4#

This version does not fully copy the authors' idea as

the wS is needed to shield its initial square in “c”.

6

3263

Anton Bidlen

Slovakia

H#2 2.1.1.1 5+3

1.Rd4 Re7 + 2.Kd3 Bf1#

1.Re5 Rg6 2.Kf5 Sh4#

Unpins with dual avoidance (PE)

3264

Jean Haymann

Sde Eliyahu

H#2 b)Sb4d8 7+5

a) 1.Ke5 Rg5 + 2.Qf5 Bg7#

b) 1.Kd5 Ba2 + 2.Rc4 Ra5#

Excellent pin-interferences with an additional interference by white’s 1st move (PE)

3265

Jean Haymann

Sde Eliyahu

H#2 2.1.1.1 10+12

1.Bg4~ (h3,f5) Sf4 2.B~ Be3# but Bg4 is pinned by Rh4!

sol: 1.Rf3 Sf4 2.Qe6 Be3#

1.Bg4~ (f3,e2) Kd2 2.Qd5+ Bd4# but Bg4 is pinned by Rh4!

sol: 1.Rf5 Kd2 2.Qd5 + Bd4#

Goethart + opposite effect (unpinning before closure) (author)

To give a mate by the R/B battery the flights d3 & d5 must be taken care of. 1…Sf4 guards

both, but black must first unpin the knight. The unpinned black bishop now interferes with

the mate and an interference by the pinned black queen does the job. Using 1...Kd2 to guard

d3 necessitates 2.Qd5 to block d5. Now, 1.Rf5 is played first to make an anticipatory

interference of BBg4 which will be unpinned by the cross-check mate. Excellent (PE)

3266

Emanuel Navon

Holon

H#2 2.1.1.1 4+14

1.Sf4 Sd3 2.Se3 Be5#

1.Rb3 Bb4 2.Sd2 Sxc2#

Theme: Avoidance of wrong move order. In the initial position of an orthodox helpmate in

two, the 1st and the 2nd Black`s moves are legal in each solution. The wrong order of

Black`s moves (try) fails due to specific harmful effect which occurs in the 1st White`s

move. The 1st and the 2nd Black`s moves must be played by different units in each solution

(author)

Composed for a thematic tourney with the above-mentioned theme, black’s move order is

determined by the need to evacuate squares for W1. Unified double interferences (PE)

3267

Yuri Gorbatenko

Russia

H#2 2.1.1.1 5+11

1.Qxf2 Rc5 2.Rd5 Qxe4#

1.Qxe2 Qc7 2.Re5 Rxd4#

Capture of white pieces by the retreating BQ and exchange of roles between WRd5 and the

WQ (PE)

'd'd'd'g d'd'd'$' 'd'd'd'd d'drd'd' 'd'dkd'd d'd')Nd' 'I'd'dBd d'd'd'd'

'd'd'G'd I'd'd'd' Rd'dPd'd d'd'd'd' 'H'dk4Rg d'dqd'd' 'd'd'd'd 4Bd'd'd'

'dRd'dBd d'd'dqd' ')')'4rd dpG'0'dp 'dkd'db$ )pd'd'0' ng'dN)'d d'dKd'd'

'd'd'd'd d'd'd'd' '0'G'I'd dpdpdBd' b4pi'dpd d'dnd'g' 'dpdrd'1 d'd'Hnd'

bd'd'I'g d'd'd'dQ 'd'd'd'd d'dRd'd' 'h'4r0'd d'dk1pd' 'd'0RG'd h'd'd'd'

7

3268

C. Jonsson O. Comay

R. Wiehagen

Sweden/T. Aviv/Germany

H#2 b)ka6a5 6+4

a) 1.Bxe3! (1.B~?) Rb5 2.Rd4 Sc5#

b) 1.Rxe4! (R~?) Bb5 2.Bd4 Sc4 #

Themes: Zilahi, white Grimshaw, Black Grimshaw, hideaway by capture, model mates

(authors)

Square b5 must be guarded to obtain mates. To do this we have line opening towards b5 and

unpinning by either the white R or B. The combination

3269

Yoel Aloni

Netanya

H#2.5 b)Bd2c6 6+11

a) 1...Bxb4 2.Kf5 e4 + 3.Ke5 Bd6#

b) 1...Bxb5 2.Kf3 Ra3 3.Sg4 Bc6#

Nice line opening play with indirect batteries (PE)

3270 Paz Einat Nes Ziona

H#3 2.1.1.1 6+8

1.Be1 Kxg5 2.fxe3 Kf4 3.e2 Ke4#

1.Bg3 exf4 2.Ke3 fxg5 3.Kf4 g6#

In one solution the WK opens the battery along the battery line and in the other the WP does

the job. The matching movement of the WK in one solution and the BK in the second is also

part of the idea (author)

3271

Alexey Ivunin

Alexander Pankratiev

Russia

H#3 4.1.1.1 3+10

1.Kc3 Rxd1 2.Kb2 Bxe5 + 3.Ka2 Ra1#

1.Qe4 Rf5 2.Qd3 Rxb5 3.Se4 Be5#

1.Qd5 Bh4 2.Ke5 Bxd8 3.Re4 Bf6#

1.Ke4 Bf2 2.Kf5 Kh7 3.Kf6 Bh4#

Four solutions but I cannot find unifying elements (PE)

3272

Michail Gershinski

Alexander Pankratiev

Russia

H#3 b)pc6b6 3+10

a) 1.Bd5 Bf4 2.Sf5 Bb8 3.Sd6 Ba7#

b) 1.Rh5 Rh1 2.Rd5 Rh7 3.Sd6 Rc7#

One of the pin lines is abandoned and the mate is given from the other side (PE)

'd'd'd'd d'd'd'dK k)'d'd'd d'g'd'dR 'hrdNd'd d'd'H'd' 'd'd'd'd d'd'dBd'

rd'd'd'd 4'd'd'd' Qd'dph'd Ipd'd'd' R0'd'dkd d'd')'g' PdnG'0'd d'd'dbd'

'd'd'd'd d'd'd'd' 'dnd'I'G d'd'dP0' 'd'd'0'g d'0')Pd' 'dpi'dPd d'drd'd'

'd'g'dKd d'd'd'd' 'd'hpd'd dpd'1'd' 'dri'd'd dpd'0'G' 'd'd'd'd d'dndRd'

'd'd'd'd d'd'd'd' 'dpd'dpd 0pi'd'd' '0nh'd'd d'd'Gbdr Kd'd'd'd d'$'d'd'

8

3273

Christer Jonsson

Sweden

H#3 2.1.1.1 4+8

1.Bc4 Bc5 + 2.Kd5 Bd4 3.exd4 Rf5#

1.f5 Rf4 2.exf4 Bf8 3.Ke5 Bg7#

Zilahi with active sacrifices (PE)

3274

Anton Bidlen

Slovakia

H#3 2.1.1.1 4+4

1.b2 Ra6 2.b1=B Bb2 3.Be4 Rf6#

1.Bh3 Ra2 2.Kg4 Rg2 + 3.Kxh4 Bg5#

Self-blocks and model mates (PE)

3275

Misha Shapiro

G. Costeff O. Comay

Israel/USA

H#3 2.1.1.1 6+13

1.Sxe6 + fxg8=B 2.Sf8 Bxd5 3.c1=B Bb3#

1.Sxg6 + fxg8=R 2.Sf8 Rxg4 3.c1=R Rd4#

Switchback, crosschecks, mutual minor promotion, minor promotion with delayed reason

(authors)

Unified play with corresponding minor promotions and line openings (PE)

3276

Okan Pandar

Turkey

H#3 1.2.1.1.. 8+9

1.Rf6 Re6 2.Rf5 + Rf6 3.Re5 Ra6 #

1… Rf5 2.Re6 + Rf6 3.Re5 Ra6 #

An improvement with co-authorship:

Okan Pandar & Daniel Papack

Turkey’Germany

H#3 1.2.1.1.. 2+8

3277

Alexey Ivunin

Alexander Pankratiev

Russia

H#3.5 4.1.1.1 3+7

1...Bxc3 2.Bf7 Ba5 3.Ke5 Rg5 + 4.Kf6 Bd8#

1...Rd1 2.Kd6 Bxf4 + 3.Ke7 Rd8 4.Bf7 Bg5#

1...Kb1 2.Kc4 Kc2 3.Kb4 Bxc3 + 4.Ka3 Ra1#

1...Be3 2.Kc6 Bxc5 3.Kb7 Rg7 + 4.Ka8 Ra7#

Three matching mating positions in the first two solutions but not in the other two (PE)

'd'd'd'd d'0KGpd' 'dPd'd'd d'db0'd' 'd'ipd'd d'd'0'd' 'd'd'$'d g'd'd'd'

'd'd'd'd d'd'd'd' 'd'd'd'd d'd'dkdp 'd'd'db) dpd'd'd' 'd'd'd'd $'G'I'd'

'd'dKhr1 d'd'0Pd' 'dpdP0P0 d'dpdPd' 'd'd'dpd d'd'0'd' Rdpd'd'd d'dk4'd'

b4'd'd'g ind'd'1' 'd'drd'd dP0P$'d' 'dPd'0'd d'd')'d' Pd'd'd'd IBd'd'd'

'dbd'd'd dpd'd'd' 'd'dqd'd d'd'd'd' 'd'd'4R0 d'd'0'dK 'd'd'dnd d'd'd'dk

'h'd'dbd d'd'd'd' 'd'dpd'd d'0kd'd' 'd'd'g'd d'0'd'd' 'd'G'd'd I'd'd'$'

1.Rf5 Rf4 2.Rg5 + Rf5 3.Rg4 Rf1#

1… Rg5 2.Rf4 + Rf5 3.Rg4 Rf1#

9

3278

Michail Gershinski

Alexander Pankratiev

Russia

H#3.5 2.1.1.1 3+10

1...Bxb5 2.Bd4 Bd7 3.Rb3 Ra5 4.Re3 Bf5#

1...Bc2 + 2.Ke5 Rxa3 3.Bd4 Rxf3 4.Se6 Rf5#

Model mates with exchange of roles by the WR & WB, but this is well known (PE)

3279

Valery Barsukov

Russia

H#4 2.1.1.1 2+7

1.Rc5 Ka2 2.Rf5 Kb3 3.Ke5 Kc4 4.Bf6 Re1#

1.Re2 Rg1 2.Re6 Kc2 3.Ke5 Kd3 4.Sf6 Rxg5#

Matching mating position from two sides of the BK with different self-blocks on f6 (PE)

3280

Yoel Aloni

Netanya

S#2 11+7

1.Sc7 ! [2.e8=R,Q + Se6#]

1...Sd~ 2.Qxc2 + Sxc2#1...Sd3 2.Qa8 + Sc6#

A version with 2+2 arrangement can be achieved (PE)

S#2 13+9

1.Rc8 ! [2.Re8 + Se6 #]

1...Qxh3 2.Re1 + Se2 #

1...Sbd5,c6,a6 2.Qxc2 + Sxc2 #

1...Sd3 2.Qa8 + Sc6 #

3281

Beni Priel

Givatayim

S#3 11+11

1.Bb4 ! [2.Sg7 + Bxg7 3.Qe5 + Bxe5#]

1...cxd6 2.cxd5 + Kf7 3.Sxh6 + Bxh6#

1...exd6 2.Bg6 ~ 3.Qe5 + dxe5#

Nice differentiation between the two captures on d6 )PE)

Kd'd'd'd dpd'd'd' R4'0'd'd dpd'd'd' Bdpdkh'd h'g'dpd' 'd'd'd'd d'd'd'd'

'd'dnd'd d'd'd'd' 'd'0'i'd d'd'd'g' 'd'd'0'd 0'd'd'd' 'drd'd'd dKd'dRd'

'd'dNdBI d'd')'dP 'd'd'd'd dpd'd'd' Qh'hk)Pd d'd')'d' pdpd')'d g'd'H'd'

'dqdrg'd d'0'0'dB 'dPHkd'0 d'dpdNdp 'dP!pI') d'd')')' 'd'G'd'd d'd'd'db

10

3282

Beni Priel

Givatayim

S#3 12+5

1.g3 ! zz

1...Kd5 2.Se3 + Kxe4 3.Re8 + Se6#

1...Sc7 2.Sd2 + Kd5 3.Rd8 + Sd7#

Harmonious variations in which the BS is self-unpinned by the movement of the BK (PE)

3283

Anatoly Styopochkin

Russia

S#9 9+3

1.e4+? dxe3 (e.p.)#?

1.Kd6! Ke4 2.c7 Kf5 3.c8=R! Ke4 4.Rg7 Kf5 5.Kd5 Kf6 6.Qb6+ Kf5 7.Qf6+ Kxf6

8.Rc6+ Kf5 9.e4+ dxe3 (e.p.) #

An interesting maneuver in which the WQ must disappear, the block on c6 restored, ending

with a cute e.p. battery mate (PE)

3284

Anatoly Styopochkin

Russia

S#10 7+4

set 1...exf2#

1.Bb3! Kd3 2.Qf3 Kd4 3.Bxe3+ Kd3 4.Qf2 Kxe4 5.Kh1 Kd3 6.Qf3 e4 7.Qf4 Ke2

8.Qxe4 Ke1(f1) 9.Bd2+ K ~ 10.Qg2+ hxg2#

Problems with immediate set mate either restore the mate or provide a different one after a

long maneuver. Here the latter is the case, but the maneuver seems rather technical (PE)

3285

Semion Shifrin

Michael Grushko

Nesher/Kiriat Bialik

H#4.5 b)Pe2d2 3+2

c) e3=r ParrainCirce

Grasshopper <

a) 1...Kxe3 2.Kg4-h4[+bPf3] Ke4 3.fxe2 Ke4-f4[+wPf2] 4.e1=G Gf3 5.Gg3 fxg3#

b) 1...dxe3 2.Kg4-h5[+bPf4] Ke5 3.Kg6 exf4 4.Kg6-h7[+bPg5] Kf6 5.Kh6 fxg5#

c) 1...Kxe3 2.Kg4-h3[+bRf2] Ke4 3.Rxe2 + Ke4-f3[+wPf1] 4.Rh2 Gf2 5.Rg2 fxg2#

Three chameleon-echo mates using nicely the ParrainCirce condition, not only for moving

the pieces to the right places, but principally for the mate. For example, in the mating

position of “a” the BK cannot move to h5 since the captured BP will be placed on g4 with

the grasshopper aiming at the BK (PE)

ndRd'IRd d'd'dPG' '0'd'd'd dPh'dPd' QgkdNd'd d'd'd'd' 'dNdPdPd d'd'd'd'

'd'd'd'd d'd'd'd' 'dPd'dRG d')KdkdP 'dP0'd'd d'drd'd' 'd'dPd'd dQd'd'd'

'd'd'd'd d'd'd'd' 'd'd'd'd d'd'0'd' 'd'dPd'd d'd'0'dp 'dBdkG') dNd'd'IQ

'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd<d' 'd'I'dkd d'd'0'd' 'd'dPd'd d'd'd'd'

11

3286

Michael Grushko

Kiriat Bialik

Ser-H#19 2+3 b) Rotate 2700 Ser-H#15

ABC PWC Take&Make

Grasshopper <

a) 1.Ke8 2.Kf8 3.Kg8 4.Kh7 5.Kh6 6.Kg5 7.Qh6 8.Kh4 9.Pf4 10.Pf3 11.Pf2 12.Pf2-

f1=R 13.Rf5 14.Rg5 15.Pxg5-g1=Q[+Rf6] 16.Rg6 17.fxg6-g5[+Rf7] 18.Rh7

19.Qb6 Qxh6-f4[+bQb6] #

b) 1.Kc4 2.b5 3.b4 4.b3 5.b2 6.b1=Q 7.Qb8 8.Qxd6-d7 [+Pb8=B] 9.Ba7 10.Bd4

11.Kxd4-e5[+Bc4] 12.Bd5 13.Pxd5-h1=Q[+nBc6] 14.Bf3 15.Qd6 Bxh1-h8[+Qf3] #

The mates in the two phases are very different, I prefer the second one (PE)

3287

Hubert Gockel

Germany

H#2 b) e2=q 13+7

Superguards

a) Mate is, when - The two bSS are gone - and this can only be achieved by wPe7, - bRe2 no

longer guards bKe6 - therefore he must move to c5 or h4

1.Rc2 e7xf8=R (=Q?) 2.Rc2xc5 Rf8xd8 # d5 must be reguarded

1.Rh2 e7xd8=R (=Q?) 2.Rh2xh4 Rd8xf8 # f5 must be reguarded

b) bQe2 must hide on a3 or b3 (squares unreachable for the bR)

1.Qe2xa2+ e7xd8=Q (=R? does not parry the check on B1) 2.Qa2xb3 Qd8xf8#

1.Qb2 e7xf8=Q (=R? does not parry the check on B2) 2.Qb2-a3+ Qf8xd8#

Promotions to wQ take care for the necessary cross checks

All comments by the author

The “Superguards” condition offers very interesting possibilities, and these are explored in

this problems. Both BRe2 and BQe2 must hide so they are unable to guard the BK on the e-

file. WPe7 captures both BS’s, and the nature of the promotion is determined by the need to

enable capture of c5 & h4 by the BR and the need to parry checks in the hideaway moves of

the BQ (PE)

3288

Ehud Goldberg

Tsofit

H#2.5 2.1.1.. 3+9

ParrainCirce

1...Rxb2 2.Bc3-g7[+bQf6] Rb3 + 3.Rxb3 Se1-d3[+wRa5] #

1...Rxb2 2.Rb4-b8[+bQb6] Sd3 3.Bxb2 Sd3-c5[+wRa4] #

Nice ODT Bristol moves and unified combination by the WR and WS to arrive at the mating

positions (PE)

3289

S. Luce & C. Feather

France/UK

Ded. Michael Grushko

Ser-H#12 3+5

ABC Take&Make

1.d1=Q 2.Qf3 3.d3 4.d2 5.d1=B 6.Bxc2-c3 7.Bg7

8.e2 9.e1=R 10.Re6 11.Rg6 12.Qb3 axb3-g8=S # AUW

Nice promotion task: three black promotion and one white knight promotion for the mate

(PE)

'd'd'd'd d'dkdpd' 'd'd')'d d'd'dPd' 'd'd'?'d d'd'd'd' 'd'd'd'd d'd'd'd'

'dNh'h'd d'd')'d' 'dPdkdP4 Ip$PdPd' 'd'd'dpH dPdPd'd' Pd'drd'd G'd'd'd'

'd'd'g'g d'd'd'd' 'd'd'd'd d'd'd'd' '4'dpd'd i'g'd'd' '1Kd'd'0 dRd'H'dr

'd'd'd'd d'd'd'dp 'd'd'd'i d'd'd'd' 'd'0'd'I d'd'0'd' PdP0'd'd d'd'd'd'

12

3290

H#2 b) d3=q 5+9

c)bc4a7 d)bc4b8 Lion Qq

a) 1.Qg2 Qf3 2.Bd5 Qh1#

b) 1.Qg6 Qf5 2.Bd3 Qh7#

c) 1.Qe7 Qe5 2.Be3 Qe8#

d) 1.Qb4 Qd4 2.Bf4 Qa4#

A black lion offers a hurdle for the mate, from a position in which it cannot move away.

Each of the four white lions gives the mate, in turn, in each of the four solutions (PE)

3291

Vaclav Kotesovec

Czech Republic

HS=13.5 2.1.1.. 1+5

BishopHopper b

1...Kf3 2.Kb1 Ke2 3.Kc2 Bb3+ 4.Kc3 Kd1 5.Kd4 Be5 6.Kd5 Be4 7.Kd4 Bc3 8.Kd3

Bec2 9.Kc4 Bd5 10.Kb4 Ba5 11.Kc3 Bd2 12.Kb3 Kc1 13.Ka2 Bd1 14.Ka1 Bb3=

1...Bh5 2.Ka2 Bf3 3.Kb3 Bc2 4.Kc4 Kh5 5.Kd5 Bc6+ 6.Ke5 Bf6 7.Kf5 Bg6 8.Ke6

Bd5 9.Kd7 Be8 10.Ke7 Bd8 11.Kf6 Bg5 12.Kf7 Kh6 13.Kg8 Bh5 14.Kh8 Bf7=

The white king is stalemated on the two opposite corners of the board. The maneuver is

rather complicated, with the WK leading the black bishop-hoppers to the needed squares. It

is amazing how the composer managed to find two unique long solutions leading to echo-

positions with the WK on a1 and h8 (PE)

3292

Semion Shifrin

Nesher

#3 Dummy x 12+16

Grasshopper <

1.Bxd5 ! [2.Sd4 + cxd4 3.Be6#]

1...Rc3 2.Sd2 ~ 3.Bxe4# 2...Bxd5 3.<xd5# 2...Rc4 3.<xd3#

1...Sc3 2.exf6 ~ 3.Qe5# 2...Sc6,Se6,Sxf7 3.Qe6#

1...Bc3 2.Kh2 ~ 3.Bxe4# 2...Bxd5 3.<xd5#

1...<d7 2.Qxd7 + Se6 3.Qxe6#

1...<d6 2.f8=< + <xf8 3.Qh7# 2...fxe5 3.Qxe5# 2...Sf7 3.Qe6#

The moves to c3 defend by allowing the a1 grasshopper to guard d4, but they produce self-

obstructions with nice dual avoidance (PE)

3293

Sergej Smotrov

Kazakhstan

H#3 2.1.1.. 3+3

Masand

1.Ke5 d4[c5=w] + 2.Kd5 Kd3 3.c6 Re5#

1.c4 d3[c4=w] + 2.Kd4 Kd2 3.c5 Re4#

Chameleon-echo mates with change of color of one black pawn (PE)

'd'd'!'d d'd'd'd' 'd'd'd'd d'dqd'd' 'dbdk1'0 d'dp1'dp pd'd'd'! I'd'dQ!'

'd'd'd'd dbd'd'd' 'd'd'd'd d'd'd'd' bd'd'dkd d'd'd'd' 'g'd'd'd I'dbd'd'

'd'h'?'d d>0'!Pd' 'dBd'0'0 d<0p)kdP ng'dXd') 4'dpdNGP bd'd'dKd ?'d'd'd<

'd'd'd'd d'0'd'd' 'd'd'd'd d'0'd'd' 'd'dkd'd d'd'd'd' 'd')Kd'd d'd'$'d'

Mikhail Khramtsevich

Aleksandr Bulavka

Belarus

13

3294

Adrian Storisteanu

Canada

-1(w,b) & h=2 0+3

Circe assassin

b)kb7f8

a) – 1.Rh1xNb1[+bNb1,-wRb1] Ka8xRb7 [+wRh1,-wRh1] & 1.Nc3 Rb7-a7+

2.Nc3xa7[+wRa1,-bNa1] Rh1-b1=

b) – 1.Qd1xNb1[+bNb1,-wQb1] Ne7xQb1 [+wQd1,-wQd1] & 1.Ne3 Qg6

2.Ne3xd1[+wQd1,-bNd1] Qd1-d6=

The use of circe assassin with retraction is tricky. Here it is used to reach two different

stalemate positions using rooks in one solution and queens in the other (PE)

3295

Alberto Armeni

Italy

#2 Neut.Rook R 12+6

1.Ra7 ? zz.

1...Bxf2 2.cxd4# 1...Sb1 2.Ra5# 1...Sc2 2.Ra5#

1...nRxd6 2.Re6# 1...e3 2.Bg7#

but 1...Sb5 !

1.Rb7 ! zz.

1...Bxf2 2.cxd4# 1...Sb1 2.Rb5# 1...Sc2 2.Rb5#

1...Sb5 2.Rxb5# 1...Rxd6 2.Re6# 1...e3 2.Bg7#

Neutral pieces are not usually used in antagonistic stipulation and seem to offer many

possibilities (PE)

3296

Miroslav Bílý

Czech Republic

H#5 2.1.1.. 3+5

Grasshopper <

1.Ra3 + Kg4 2.Rc3 <b4 3.<b3 <d2 4.Kd4 Kf4 5.<d5 <b4#

1.Ra4 Kf4 2.<g3 Ke3 3.<d3 Kf4 4.Rb4 <a5 + 5.Kd4 c3#

Two different, but nice, mating positions. The tempo move in the 1st solution is of note (PE)

3297

Udo Degener

Germany

H#6 b)kd6c7 2+2

KoeKo

a) 1.c1=S Kd2 2.Sd3 Ke3 3.Se5 Kf4 4.Sf7 e8=S 5.Sg5 Kf5 6.Se4 Ke6 #

b) 1.c1=Q Kc2 2.Qd2 Kc3 3.Qd7 e8=Q 4.Qc6 Qc8 + 5.Kb6 Qa6 + 6.Ka5 Kb4 #

The promotion play is interesting: the promoted black piece must get close to WPe7 so it

can promote (PE)

'd'd'd'd dkd'd'd' 'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'd'd'd'd .,d'd'd'

Kd'd'd'd d'dRH'd' 'dP)'dRG d'd'i'd' 'dp$pd'd h')pdpd' 'd')')'d d'd'd'G'

r?'d'd'd d'd'd'd' 'd'd'd'd d'4kd'd' 'dpd'd'd d'd'd'I' 'dPd'd'd d'd'='d'

'd'd'd'd d'd')'d' 'd'i'd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'dpd'd'd d'dKd'd'

14

3298

S. Trommler F. Pachl

Germany

HS#4 b)ne4f4 5+14

a) 1.Kf4 Sd2 2.Be4 Bf5 3.Ke5 Rf1 4.Bc6 + Bd7#

b) 1.Ke4 Se2 2.Rxb4 Rd4 + 3.Ke5 Bf3 4.Rb8 + Rd8#

Excellent harmony with Umnovs, switchbacks and dual-avoidance play by the black knight

(PE)

3299

Eric Huber

Romania

H#2.5 b)Pe7e5 4+1

PartialParalysis

Neutral pawns P

a) 1...Pc7-c8=Q + 2.Qh8 + Pe7- e8=R 3.Qc3 + Qc8# Rundlauf Q

b) 1...Pc7-c8=R 2.Ka5 Pd7-d8=Q + 3.Qe7 Qc7#

Chameleon echo mates Specific use of PartialParalysis a) the bK is paralysed by the nQ. The

nQc8 is partially paralysed by nRe8 and cannot move orthogonally. The nQc8 is also

partially paralysed by wKb8 and cannot play 4.nQxd7. b) the bK is paralysed by the nQ.

The nQc7 is partially paralysed by nRc8 and wKb8. The only diagonal move would be

4.nQxe5 but it would be an illegal self-check. Definition of Partial Paralysis: If the piece X

is attacked by the piece Y then X cannot move as Y (author).

A very intricate paralysis net (partial one, as defined) – difficult to grasp but very rewarding

(PE)

3300

Ľuboš Kekely

Slovakia

Pser-H#23 5+5

TransmutedKings

1.Kb6 2.Kc7 3.Kd8 4.Ke7 5.Kf6 6.Kg5 7.Kxg4 8.Kh3 9.Kh2 10.Kg1 11.Kf1 12.Kxe1

13.Kd1 14.Kc1 15.Kb2 16.Ka3 17.Kxb4 18.Ka3 19.b4 20.b3 21.b2 22.b1=B + Kc4

23.Ka2 Kxd4#

The BK almost completes a full round, but the motivation is to capture WPb4, promote b5 to

bishop with a check prompting the W move. The mate utilizes the TransmutedKing

condition (PE)

3301

Vito Rallo

Italy

H#3 2.1.1.. 1+2

Sentinelles

1.Kg4[+bPh5] Kg7[+wPh7] 2.h4 h8=Q 3.Kh5[+bPg4] Qxh6#

1.Kg5[+bPh5] Kg8[+wPh7] 2.Kf5[+bPg5] h8=Q 3.Kg6[+bPf5] Qg7#

WC: Switchback noir, Switchback de Roi, Promotion (author)

The nice sentinel-based maneuvers end with simple mates (PE)

'd'dkd'd d'0'dp)' 'd'd')'d d'd'IBdr '0'$ndb0 d'g'0'0p 'd'd'dpd d'drd'd'

'I'd'd'd d')P)'d' kd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'd'

'd'd'd'd d'dpd'd' kd'0'd'd dpdBd'd' ')'0'dPd d'dKd'd' 'd'd'd'd d'd'G'd'

'd'd'd'd d'd'd'dK 'd'd'd'0 d'd'd'dk 'd'd'd'd d'd'd'd' 'd'd'd'd d'd'd'd'

15

3302

Anatoly Styopochkin

Russia

HS#5.5 b) -pc4 2+4

KoeKo GridChess

a) 1...0-0-0 2.exd8=S Re8 3.Sf7 Re3 4.Ke2 Re8 5.Kd3 Rg8 6.Sh8 Rd8#

b) 1...Rd8 2.exd8=B 0-0 3.Be7 Rf4 4.Bg5 Rh4 5.Be3 Rh7 6.Kf2 Rf7#

Using these two limiting conditions (each move must result in contact with another piece but

also move across the grid-lines, which I added for clarity) one can reach rather absurd

mating positions (PE)

rd'dkd'4 d'd')'d' 'd'd'd'd d'd'd'd' 'dpd'd'd d'd'dKd' 'd'd'd'd d'd'd'd'