1
Exercice 4 : Pour 8 valeurs de x, 2, 3, 5, 1, 4, 3, 2, 4, calculer x, m=moyenne(x), (x)², (x-m), (x-m)², (1/n) (x-m)² et (1/n)x² - m 2 =2+3+5+1+4+3+2+4= n=8 donc = 1 = 1 8 × 24 = 2 = (24) 2 = () = (2 3) + (3 3) + (5 3) + (1 3) + (4 3) + (3 3) + (2 3) + (4 3) ()=(1) + (0) + (2) + (2) + (1) + (0) + (1) + (1) = () 2 = (2 3) 2 + (3 3) 2 + (5 3) 2 + (1 3) 2 + (4 3) 2 + (3 3) 2 + (2 3) 2 + (4 3) 2 () 2 =1+0+4+4+1+0+1+1= 1 () 2 = 1 8 × 12 = . Pour 1 2 2 Il faut d’abord calculer 2 2 = 2² + 3² + 5² + 1² + 4² + 3² + 2² + 4² = 4 + 9 + 25 + 1 + 16 + 9 + 4 + 16 = 84 1 2 2 = 1 8 × 84 3 2 = 10.5 9= , 1,5 est la variance de l’échantillon.

TD4_4

  • Upload
    ok

  • View
    213

  • Download
    0

Embed Size (px)

DESCRIPTION

f

Citation preview

  • Exercice 4 : Pour 8 valeurs de x, 2, 3, 5, 1, 4, 3, 2, 4, calculer

    x, m=moyenne(x), (x), (x-m), (x-m), (1/n) (x-m) et (1/n)x - m2

    = 2 + 3 + 5 + 1 + 4 + 3 + 2 + 4 = n=8 donc

    = 1 = 18 24 =

    2 = (24)2 =

    ( ) = (2 3) + (3 3) + (5 3) + (1 3) + (4 3) + (3 3) + (2 3) + (4 3) ( ) = (1) + (0) + (2) + (2) + (1) + (0) + (1) + (1) =

    ( )2 = (2 3)2 + (3 3)2 + (5 3)2 + (1 3)2 + (4 3)2 + (3 3)2 + (2 3)2 + (4 3)2 ( )2 = 1 + 0 + 4 + 4 + 1 + 0 + 1 + 1 =

    1( )2 = 18 12 = .

    Pour 1

    2 2

    Il faut dabord calculer 2

    2 = 2 + 3 + 5 + 1 + 4 + 3 + 2 + 4 = 4 + 9 + 25 + 1 + 16 + 9 + 4 + 16 = 84 1

    2 2 = 18 84 32 = 10.5 9 = ,

    1,5 est la variance de lchantillon.