PC_devoir2-tr1-2012-2013

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  • 7/29/2019 PC_devoir2-tr1-2012-2013

    1/4

    0.5

    1

    0.5

    0.5 11

    0.51

    0.50.5

    :2

    -1-

    -1-R1R2C

    GLX

    U

    C .:R1=5 K-I:

    K1t=0R1-2-.

    1.UC.

    2.:t

    CU Ae B

    .BA.

    3.B.

    4.C. 5.i(t)t=4ms.6." "(Temps de monte )t10%

    90%.:t=.Ln(9).-II

    k2t=0R2.-3-.

    1.UC.2.UC= E.e

    -mtmR2C.3.R2.4.t=2ms.

    0 2 4 6 8 10

    2

    4

    6

    8

    t(ms)

    UC(V)0 2 4 6 8 10

    2

    4

    6

    8

    t(ms)

    UC(V)-2-

    -3-

    VE I0

    R1

    K1

    2

    R2UCE

    UR

    -1-

    I)7(

  • 7/29/2019 PC_devoir2-tr1-2012-2013

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    .ClCH2CO2H.

    C=5.10-2mol.L-1.25:=0,3 S.m-1.

    1..2.).AHA-.(3.[H3O

    +]:(H3O

    +)(A

    -).: .

    (H3O+) = 35. 10

    -3S.m

    2.mol

    -1; (A

    -) = 4.10

    -3S.m

    2.mol

    -1

    4..5.pH.6.KAH.

    7.C2=1,8.10-2

    mol.L-1

    . pH:pH=2,37.2.

    .K2..K

    .

    :a1 = 1,6.1012

    Bq.1.137CsX)(.

    2.E.

    3.

    137Cs

    ans

    -1

    s

    -1.

    (1ans=365jours)4.137Cst=0.:NA=6,02 10

    23mol

    -1.

    5.:( )( ) dN ta tdt

    .:a(t) = .N(t).

    N(t)t.

    6.a0t=0.

    7.a1.

    1

    1.5

    10.5

    0.5

    0.5

    1

    II)6(

    )7(

    0.511

    10.51

    0.51

    0.5

    :137

    Cs

    :137g.mol-1

    t1/2:30 ans

    :-.

    (t=0):m0=2g

    13755Cs136,87692 u

    X136,87511 u

    -0,00055 u1u= 931,5 MeV.c-2

    I Xe Cs Ba La

    Z=53 Z=54 Z=55 Z=56 Z=57

  • 7/29/2019 PC_devoir2-tr1-2012-2013

    3/4

    1.

    I

    I-:1.:

    1

    1 1

    R C

    C

    C C

    E U U

    dU

    E R i U R C Udt

    2.:t

    CU Ae B

    C

    tdU

    dt

    Ae

    :

    1

    1(1 )

    1

    t t

    t

    C

    C

    AE Ae B R e

    E B Ae R

    :

    1 1(1 )

    01

    0C C

    E B B E

    R R

    A:t=0:UC(t=0)=0

    :0( 0) 0

    Ct B

    A B E

    U Ae

    :

    1(1 )

    t

    C R CU E e

    3.:B=E=8V=2ms.4.:

    1

    1

    74.10 0.4

    R C CR

    C F F

    5.:( ) .Ct

    dUi t C

    dt

    EC e

    :

    1

    1

    ( )

    ( )

    .

    t

    t

    i t R C

    i tR

    E

    C e

    Ee

    t=4ms:43

    42( ) 2,16.10

    5.10

    8 msmsi t Ae

    6.t1UC:10%Et2UC:90%E: .

    1 1

    2 2

    1

    2

    ( ) 100

    ( )100

    10

    (1 ) 1 0,1

    90(1 ) 1 0,9

    t t

    C

    t t

    C

    t

    t

    E

    U E e e

    EU E e e

    :

    1

    2

    11

    22

    (0,9) (0,9)

    (0,1) (0,1)

    0,9

    0,1

    t

    t

    tLn t Ln

    tLn t Ln

    e

    e

    :t= t2-t1:(0,1) (0,9)

    0,9( (0,9) (0,1)) ( )

    0,1

    (9)

    t Ln Ln

    t Ln Ln Ln

    t Ln

    II-:1.:

    2

    2

    0

    0

    R C

    CC

    U U

    dUR C Udt

    2.:mtCU EeC mt

    dUEm

    dte

    :

    2

    2

    0

    (1 ) 0

    mt mt

    mt

    Cm

    Cm

    Ee R e

    Ee R

    :21 0CmR :

    2 2

    1 1m

    CR

    3.:2=4ms.:2 2R C :

    22 10R k

    C

    4.t=2msUC=4,8 V: .

    2 7 2

    6

    1 1.4.10 .4,8

    2 2

    4,60.10

    CCU

    1.137 137 055 56 1Cs Ba e 2.:

    137 137 2

    3 2 2

    ( ( ) ( ) ( )).

    1,26.10 931.5 . .

    1,174

    E m Ba m e m Cs c

    u Mev c c

    E Mev

    3.:

    12

    (2) (2)

    30

    Ln Ln

    t :

    2 12,31.10 ans

    10 1(2) 7,327.1030 365 24 3600

    Lns

    I

    2

    920132012

    II

    J

  • 7/29/2019 PC_devoir2-tr1-2012-2013

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    4.:23 21

    0 0

    2.6,02.10 8,79.10

    137A

    mN N N

    M

    5.:0

    ( ) tN t N e :0. . ( )tdN dN N e N t

    dt dt

    :( )dN

    a tdt

    :( ) . ( )a t N t

    6.:( ) . ( )a t N t

    :0 0.a N

    :

    10 21 12

    0 7,327.10 8.79.10 6, 44.10a Bq

    7.:0( )ta t a e :

    0

    ( ) ta t ea

    :

    120

    120

    12

    0

    9

    ( ) 6,44.10( ) ( ) ( )

    ( ) ( ) 1,6.10( ) . .30

    (2) (2)

    60,27 1,9.10

    a t aLn Ln Ln

    aa t a tLn t t t t ans

    a Ln Ln

    t ans s

    1.2 2 2 3 2 2aq aq aqClCH CO H H O H O ClCH CO

    2.

    3.:

    3 3

    . .f H O A

    H O A: 3

    fxH O AV

    : 33 ( )f H O AH O:

    3

    3 ( )f

    H O A

    H O: . .

    3 33 3

    0,3. 7,692 .

    (35 4).10H O mol m mol m :

    3 33 7,692.10 .H O mol L

    4.:

    3 3 3

    max

    ( ) [ ]. [ ]fx n H O H O v H O

    x CV CV C :

    3

    2

    7,692.100.154

    5.10.: 1.

    5.: 3 2,11pH Log H O

    6.:

    :

    3

    ,r qH O Ak Q

    AH: 3H O A

    3fCV xAH C H O

    V:

    2

    3

    3

    H Ok

    C H O: .3k 1,39.10

    7.-:

    3 22max 2 2

    [ ] 100.23

    pHfx H O

    x C C

    -

    2

    3

    2

    3

    H Ok

    C H O:

    2.373

    2 2 2.37

    101,32.10

    1,8.10 10k

    - 1 22k kk

    .

    2 3aq aq aqAH H O H O A

    00n0=CV0

    xxn0-.xxt

    xfxfn0-.xfxf