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7/29/2019 PC_devoir2-tr1-2012-2013
1/4
0.5
1
0.5
0.5 11
0.51
0.50.5
:2
-1-
-1-R1R2C
GLX
U
C .:R1=5 K-I:
K1t=0R1-2-.
1.UC.
2.:t
CU Ae B
.BA.
3.B.
4.C. 5.i(t)t=4ms.6." "(Temps de monte )t10%
90%.:t=.Ln(9).-II
k2t=0R2.-3-.
1.UC.2.UC= E.e
-mtmR2C.3.R2.4.t=2ms.
0 2 4 6 8 10
2
4
6
8
t(ms)
UC(V)0 2 4 6 8 10
2
4
6
8
t(ms)
UC(V)-2-
-3-
VE I0
R1
K1
2
R2UCE
UR
-1-
I)7(
7/29/2019 PC_devoir2-tr1-2012-2013
2/4
.ClCH2CO2H.
C=5.10-2mol.L-1.25:=0,3 S.m-1.
1..2.).AHA-.(3.[H3O
+]:(H3O
+)(A
-).: .
(H3O+) = 35. 10
-3S.m
2.mol
-1; (A
-) = 4.10
-3S.m
2.mol
-1
4..5.pH.6.KAH.
7.C2=1,8.10-2
mol.L-1
. pH:pH=2,37.2.
.K2..K
.
:a1 = 1,6.1012
Bq.1.137CsX)(.
2.E.
3.
137Cs
ans
-1
s
-1.
(1ans=365jours)4.137Cst=0.:NA=6,02 10
23mol
-1.
5.:( )( ) dN ta tdt
.:a(t) = .N(t).
N(t)t.
6.a0t=0.
7.a1.
1
1.5
10.5
0.5
0.5
1
II)6(
)7(
0.511
10.51
0.51
0.5
:137
Cs
:137g.mol-1
t1/2:30 ans
:-.
(t=0):m0=2g
13755Cs136,87692 u
X136,87511 u
-0,00055 u1u= 931,5 MeV.c-2
I Xe Cs Ba La
Z=53 Z=54 Z=55 Z=56 Z=57
7/29/2019 PC_devoir2-tr1-2012-2013
3/4
1.
I
I-:1.:
1
1 1
R C
C
C C
E U U
dU
E R i U R C Udt
2.:t
CU Ae B
C
tdU
dt
Ae
:
1
1(1 )
1
t t
t
C
C
AE Ae B R e
E B Ae R
:
1 1(1 )
01
0C C
E B B E
R R
A:t=0:UC(t=0)=0
:0( 0) 0
Ct B
A B E
U Ae
:
1(1 )
t
C R CU E e
3.:B=E=8V=2ms.4.:
1
1
74.10 0.4
R C CR
C F F
5.:( ) .Ct
dUi t C
dt
EC e
:
1
1
( )
( )
.
t
t
i t R C
i tR
E
C e
Ee
t=4ms:43
42( ) 2,16.10
5.10
8 msmsi t Ae
6.t1UC:10%Et2UC:90%E: .
1 1
2 2
1
2
( ) 100
( )100
10
(1 ) 1 0,1
90(1 ) 1 0,9
t t
C
t t
C
t
t
E
U E e e
EU E e e
:
1
2
11
22
(0,9) (0,9)
(0,1) (0,1)
0,9
0,1
t
t
tLn t Ln
tLn t Ln
e
e
:t= t2-t1:(0,1) (0,9)
0,9( (0,9) (0,1)) ( )
0,1
(9)
t Ln Ln
t Ln Ln Ln
t Ln
II-:1.:
2
2
0
0
R C
CC
U U
dUR C Udt
2.:mtCU EeC mt
dUEm
dte
:
2
2
0
(1 ) 0
mt mt
mt
Cm
Cm
Ee R e
Ee R
:21 0CmR :
2 2
1 1m
CR
3.:2=4ms.:2 2R C :
22 10R k
C
4.t=2msUC=4,8 V: .
2 7 2
6
1 1.4.10 .4,8
2 2
4,60.10
CCU
1.137 137 055 56 1Cs Ba e 2.:
137 137 2
3 2 2
( ( ) ( ) ( )).
1,26.10 931.5 . .
1,174
E m Ba m e m Cs c
u Mev c c
E Mev
3.:
12
(2) (2)
30
Ln Ln
t :
2 12,31.10 ans
10 1(2) 7,327.1030 365 24 3600
Lns
I
2
920132012
II
J
7/29/2019 PC_devoir2-tr1-2012-2013
4/4
4.:23 21
0 0
2.6,02.10 8,79.10
137A
mN N N
M
5.:0
( ) tN t N e :0. . ( )tdN dN N e N t
dt dt
:( )dN
a tdt
:( ) . ( )a t N t
6.:( ) . ( )a t N t
:0 0.a N
:
10 21 12
0 7,327.10 8.79.10 6, 44.10a Bq
7.:0( )ta t a e :
0
( ) ta t ea
:
120
120
12
0
9
( ) 6,44.10( ) ( ) ( )
( ) ( ) 1,6.10( ) . .30
(2) (2)
60,27 1,9.10
a t aLn Ln Ln
aa t a tLn t t t t ans
a Ln Ln
t ans s
1.2 2 2 3 2 2aq aq aqClCH CO H H O H O ClCH CO
2.
3.:
3 3
. .f H O A
H O A: 3
fxH O AV
: 33 ( )f H O AH O:
3
3 ( )f
H O A
H O: . .
3 33 3
0,3. 7,692 .
(35 4).10H O mol m mol m :
3 33 7,692.10 .H O mol L
4.:
3 3 3
max
( ) [ ]. [ ]fx n H O H O v H O
x CV CV C :
3
2
7,692.100.154
5.10.: 1.
5.: 3 2,11pH Log H O
6.:
:
3
,r qH O Ak Q
AH: 3H O A
3fCV xAH C H O
V:
2
3
3
H Ok
C H O: .3k 1,39.10
7.-:
3 22max 2 2
[ ] 100.23
pHfx H O
x C C
-
2
3
2
3
H Ok
C H O:
2.373
2 2 2.37
101,32.10
1,8.10 10k
- 1 22k kk
.
2 3aq aq aqAH H O H O A
00n0=CV0
xxn0-.xxt
xfxfn0-.xfxf